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ankoles [38]
2 years ago
7

A piggy bank contains some dimes and nickels. There are 8 more dimes than nickels in the bank. There is a total of $1.40. How ma

ny of each type of coin are in the bank?
Mathematics
1 answer:
Softa [21]2 years ago
5 0

Answer:

4 nickels

12 dimes

Step-by-step explanation:

Dimes are worth .1 each while nickels are .05 each.

We have 8 more dimes than nickels. Let d represent number of dimes and n for number of nickels. This means we have d=8+n.

If all our nickels and dimes together are worth 1.4 then we have another equation .1d+.05n=1.4

Lets put our equations together:

d=8+n

.1d+.05n=1.4

‐-----------------Plug first equation into second.

.1(8+n)+.05n=1.4

Distribute

.8+.1n+.05n=1.4

Combine like terms

.8+.15n=1.4

Subtract .8 on both sides

.15n=.6

Divide both sides by .15

n=.6/.15=4

Remember there are 8 more dimes so d=8+4=12.

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Answer:

the percentage profit is 20%

Step-by-step explanation:

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