answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
soldi70 [24.7K]
2 years ago
10

What is the quotient? x + 1)3x2 − 2x + 7

Mathematics
1 answer:
melisa1 [442]2 years ago
8 0

Answer:

3x-5

Step-by-step explanation:

You might be interested in
what is the simplified form of the following expression? Assume x is greater than or equal to 0 and y is greater than or equal t
yarga [219]

the given expression is :

2(4√16x) - 2(4√2y) + 34√81x - 4(4√32y)

⇒ 8(√16x) - 8(√2y) + 34√81x - 16√32y  

⇒8×4√x - 8√2y + 34×9√x - 16√16×2y     [∵ √16 = 4 and √81 = 9]

⇒32√x - 8√2y + 306√x - 16×4√2y

⇒(32√x + 306√x) - 8√2y  - 16×4√2y      

⇒338√x -72√2y

4 0
2 years ago
Read 2 more answers
What number would you multiply the second equation by in order to eliminate the x-terms when adding to the first equation? What
alexandr402 [8]

Answer:

1. Multiply (2) by 2 to eliminate the x-terms when adding

2. Multiply (2) by 3 to eliminate the y- term

Step-by-step explanation:

Use this system of equations to answer the questions that follow.

4x-9y = 7

-2x+ 3y= 4

what number would you multiply the second equation by in order to eliminate the x-terms when adding the first equation?

4x-9y = 7 (1)

-2x+ 3y= 4 (2)

Multiply (2) by 2 to eliminate the x-terms when adding the first equation

4x-9y = 7

-4x +6y = 8

Adding the equations

4x + (-4x) -9y + 6y = 7 + 8

4x - 4x - 3y = 15

-3y = 15

y = 15/-3

= -5

what number would you multiply the second equation by in order to eliminate the y- term when adding the second equation?

4x-9y = 7 (1)

-2x+ 3y= 4 (2)

Multiply (2) by 3 to eliminate the y- term

4x - 9y = 7

-6x + 9y = 12

Adding the equations

4x + (-6x) -9y + 9y = 7 + 12

4x - 6x = 19

-2x = 19

x = 19/-2

= -9.5

x = -9.5

6 0
1 year ago
Read 2 more answers
Matthew manages the packaging department of his company. Yesterday, the department operated for only 4 hours due to a company pi
yKpoI14uk [10]

Alright, lets get started.

If Matthew wants to complete packages at an average rate of at least 39 packages per hour.

And they worked 4 hrs only due to picnic, yesterday, it means they have to make 39*4 = 156 packages.

But they made only 112 packages means they are short of 156 - 112 = 44 packages.

Suppose they are working today t hrs, and his department will complete 43 packages per hour today.

It means they are going to make 43 t packages today.

This 43 t packages includes those 44 too , which they are short of yesterday due to picnic.

So, average will be

\frac{43 t - 44}{t} = 39 (39 average given in question)

Cross multiplying

39 t = 43 t - 44

Adding 44 in both sides

39 t + 44 = 43 t - 44 + 44

43 t = 39 t + 44

Subtracting 39 t in both sides

43 t - 39 t = 39 t + 44 - 39 t

4t = 44

Dividing 4 in both sides

t = 11 hrs

Hence they have to woth 11 hrs today : Answer

Hope it will help :)

3 0
2 years ago
Read 2 more answers
PLEASE HELP ME!
algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

2.\sum_{k=1}^{4}(2k)^{2}

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

∑ = 120

3.\sum_{k=3}^{6}(2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4.  The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

\sum_{j=1}^{7}(\frac{1}{4})^{j-1}

5. -5 + -1 + 3 + 7 + 11

This is an arithmetic sequence where the first term is -5 and the common difference is 4.  The nth term is:

a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

\sum_{j=1}^{5}(4j-9)

5 0
2 years ago
If a certain number is increased by 5 one half of the result is three-fifths of the excess of 61 over the number find the number
PSYCHO15rus [73]

Answer:

= 391/11

Let say number = N

a certain number is increased by 5

= N + 5

,one-half of the result

= (N + 5)/2

Three -fifths of the excess of 61 over the number.

= (3/5)(61 - N)

Equating both

(N + 5)/2  = (3/5)(61 - N)

multiplying by 10 both sides

=> 5(N + 5) = 6(61 - N)

=> 5N + 25 = 366 - 6N

=> 11N = 391

=> N = 391/11

Step-by-step explanation:

8 0
2 years ago
Other questions:
  • What is the name of an equivalent name for 96
    5·2 answers
  • The measures in the table describe the weights of animals that visited a vet on one day, in pounds. Mean Median Mode Mean Absolu
    11·2 answers
  • Alexis has a rectangular piece of red paper that is 4 cm wide its length is twice its width she Glooze a rectangular r Alexis ha
    13·2 answers
  • Find the missing lengths:<br> LO=5 and OK=4, find OH and KH.
    9·2 answers
  • Find the values of x1 and x2 where the following two constraints intersect.
    8·1 answer
  • Which statements about the hyperbola are true? Select two options.
    6·1 answer
  • What is 8290/21 with an remainder
    10·1 answer
  • At the Yogurt Pump, all flavors of frozen yogurt are $1.75 per scoop. If a customer buys v vanilla scoops and c chocolate scoops
    7·1 answer
  • A cement mixer can hold up to 681 kilograms of cement. How many 100-pound bags of cement can be put into the mixer at one time?​
    6·1 answer
  • Mrs. Garcia’s students were asked to find 220% of 75. Each of the students had a different method.
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!