the given expression is :
2(4√16x) - 2(4√2y) + 34√81x - 4(4√32y)
⇒ 8(√16x) - 8(√2y) + 34√81x - 16√32y
⇒8×4√x - 8√2y + 34×9√x - 16√16×2y [∵ √16 = 4 and √81 = 9]
⇒32√x - 8√2y + 306√x - 16×4√2y
⇒(32√x + 306√x) - 8√2y - 16×4√2y
⇒338√x -72√2y
Answer:
1. Multiply (2) by 2 to eliminate the x-terms when adding
2. Multiply (2) by 3 to eliminate the y- term
Step-by-step explanation:
Use this system of equations to answer the questions that follow.
4x-9y = 7
-2x+ 3y= 4
what number would you multiply the second equation by in order to eliminate the x-terms when adding the first equation?
4x-9y = 7 (1)
-2x+ 3y= 4 (2)
Multiply (2) by 2 to eliminate the x-terms when adding the first equation
4x-9y = 7
-4x +6y = 8
Adding the equations
4x + (-4x) -9y + 6y = 7 + 8
4x - 4x - 3y = 15
-3y = 15
y = 15/-3
= -5
what number would you multiply the second equation by in order to eliminate the y- term when adding the second equation?
4x-9y = 7 (1)
-2x+ 3y= 4 (2)
Multiply (2) by 3 to eliminate the y- term
4x - 9y = 7
-6x + 9y = 12
Adding the equations
4x + (-6x) -9y + 9y = 7 + 12
4x - 6x = 19
-2x = 19
x = 19/-2
= -9.5
x = -9.5
Alright, lets get started.
If Matthew wants to complete packages at an average rate of at least 39 packages per hour.
And they worked 4 hrs only due to picnic, yesterday, it means they have to make
packages.
But they made only 112 packages means they are short of
packages.
Suppose they are working today t hrs, and his department will complete 43 packages per hour today.
It means they are going to make 43 t packages today.
This 43 t packages includes those 44 too , which they are short of yesterday due to picnic.
So, average will be
(39 average given in question)
Cross multiplying

Adding 44 in both sides


Subtracting 39 t in both sides


Dividing 4 in both sides
t = 11 hrs
Hence they have to woth 11 hrs today : Answer
Hope it will help :)
Step-by-step explanation:

The simplest method is "brute force". Calculate each term and add them up.
∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)
∑ = 3 + 6 + 9 + 12 + 15
∑ = 45

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²
∑ = 4 + 16 + 36 + 64
∑ = 120

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)
∑ = -4 + -2 + 0 + 2
∑ = -4
4. 1 + 1/4 + 1/16 + 1/64 + 1/256
This is a geometric sequence where the first term is 1 and the common ratio is 1/4. The nth term is:
a = 1 (1/4)ⁿ⁻¹
So the series is:

5. -5 + -1 + 3 + 7 + 11
This is an arithmetic sequence where the first term is -5 and the common difference is 4. The nth term is:
a = -5 + 4(n−1)
a = -5 + 4n − 4
a = 4n − 9
So the series is:

Answer:
= 391/11
Let say number = N
a certain number is increased by 5
= N + 5
,one-half of the result
= (N + 5)/2
Three -fifths of the excess of 61 over the number.
= (3/5)(61 - N)
Equating both
(N + 5)/2 = (3/5)(61 - N)
multiplying by 10 both sides
=> 5(N + 5) = 6(61 - N)
=> 5N + 25 = 366 - 6N
=> 11N = 391
=> N = 391/11
Step-by-step explanation: