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Luden [163]
2 years ago
12

A plate of an alloy steel has a plane-strain fracture toughness of 50 MPa√m. If it is known that the largest surface crack is 0.

5 mm long and that the value of Y is 1.1, which of the following can be said about this plate when a tensile stress of 1000 MPa is applied?
A. It is not possible to determine whether or not the plate will fracture.
B. The plate will definitely not fracture
C. The plate will definitely fracture.
Engineering
1 answer:
Ivahew [28]2 years ago
8 0

Answer:

option B is correct. Fracture will definitely not occur

Explanation:

The formula for fracture toughness is given by;

K_ic = σY√πa

Where,

σ is the applied stress

Y is the dimensionless parameter

a is the crack length.

Let's make σ the subject

So,

σ = [K_ic/Y√πa]

Plugging in the relevant values;

σ = [50/(1.1√π*(0.5 x 10^(-3))]

σ = 1147 MPa

Thus, the material can withstand a stress of 1147 MPa

So, if tensile stress of 1000 MPa is applied, fracture will not occur because the material can withstand a higher stress of 1147 MPa before it fractures. So option B is correct.

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Answer: Vo= 39.84 volts

Explanation:

Let Vo to be the voltage level of the signal,

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A ________ is only achieved through control and involves a specific change in one event (dependent variable) that can reliably b
prohojiy [21]

Answer:

Functional Relationship

Explanation:

A functional relationship is only achieved through control and involves a specific change in one event (dependent variable) that can reliably be produced by specific manipulations of another event (independent variable), and the change in the dependent variable is unlikely to be the result of other extraneous factors (confounding variables

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Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid–vapor mixture at a pressure
dezoksy [38]

Answer:

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(c). Total entropy change is dS = 0.0232 \frac{KJ}{K}

Explanation:

Given data

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dS_{ref} = \frac{Q}{T_{sat}}

Since heat absorbed by refrigerant Q = 180 KJ

dS = \frac{180}{254.23}

dS = 0.7077 \frac{KJ}{K}

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2 years ago
Suppose we store a relation R (x,y) in a grid file. Both attributes have a range of values from 0 to 1000. The partitions of thi
leva [86]

Answer:

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From the question stated, we need to define what a Grid file is

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dezoksy [38]

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