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nikitadnepr [17]
2 years ago
4

You compare the gas generated from a reaction using two antacid tablets with the gas generated from a reaction using four antaci

d tablets (consider the antacid to be the limiting reagent). At constant pressure and temperature, how do the volumes of the gases compare?
Question 4 options:

The gas generated by four antacid tablets has a greater volume


The gas generated by two antacid tablets has a greater volume


The two reactions produce the same amount of gas


I don't know
Chemistry
2 answers:
lions [1.4K]2 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

At constant pressure and temperature, <span>The gas generated by four antacid tablets has a greater volume. The answer should be the first option. </span>
Luda [366]2 years ago
6 0

Answer: The correct answer is the gas generated by four antacid tablets has a greater volume

Explanation:

In the question, it is given that pressure and temperature of the gas remain constant and we need to compare the volume of the gas produced by 4  antacid tablets and 2 antacid tablets.

As, antacid is the limiting reagent. Hence, more the tablets, more gas will be produced.

Hence, more gas will be produced by four antacid tablets than the gas produced by 2 antacid tablets.

To compare the volume, we use Avogadro's Law which states that volume is directly proportional to the number of the gas at constant pressure and temperature.

V\propto n     (At constant Temperature and Pressure)

Hence, volume will be greater for the gas produced by four antacid tablets.

Therefore, the correct answer is the gas generated by four antacid tablets has a greater volume

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If Co(NH3)63+ has a λmax at 440 nm, calculate ΔE for the complex. A) 2.72 x 10-4 kJ/mol B) 4.52 x 10-2 kJ/mol C) 2.72 x 10 2 kJ/
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<u>Answer:</u> The energy of the complex is 2.72\times 10^2kJ

<u>Explanation:</u>

To calculate the energy of the complex, we use the equation given by Planck which is:

\Delta E=\frac{N_Ahc}{\lambda}

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c = speed of light = 3\times 10^8m/s

N_A = Avogadro's number = 6.022\times 10^{23}

\Delta E = energy of the complex

Putting values in above equation, we get:

\Delta E=\frac{6.022\times 10^{23}\times 6.624\times 10^{-34}\times 3\times 10^8}{4.40\times 10^{-7}}\\\\\Delta E=2.72\times 10^{5}J=2.72\times 10^2kJ

Conversion factor used:  1 kJ = 1000 J

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