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2 years ago

A species has the following MO configuration: (σ1s)2(σ1s)2(σ2s)2(σ2s)2(σ2p)2(π2p)2. This substance is:_______.

Chemistry

1 answer:

Goshia [24]2 years ago

3 0

Answer : The correct option is, (a) paramagnetic with two unpaired electrons.

Explanation :

According to the molecular orbital theory, the general molecular orbital configuration will be,

$(\sigma_{1s}),(\sigma_{1s}^*),(\sigma_{2s}),(\sigma_{2s}^*),(\sigma_{2p_z}),[(\pi_{2p_x})=(\pi_{2p_y})],[(\pi_{2p_x}^*)=(\pi_{2p_y}^*)],(\sigma_{2p_z}^*)$

As there are 14 electrons present in the given configuration.

The molecular orbital configuration of molecule will be,

$(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^2,(\sigma_{2s}^*)^2,(\sigma_{2p_z})^2,[(\pi_{2p_x})^1=(\pi_{2p_y})^1],[(\pi_{2p_x}^*)^0=(\pi_{2p_y}^*)^0],(\sigma_{2p_z}^*)^0$

The number of unpaired electron in the given configuration is, 2. So, this is paramagnetic. That means, more the number of unpaired electrons, more paramagnetic.

Hence, the correct option is, (a) paramagnetic with two unpaired electrons.

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For the reaction n2(g) + 2h2(g) â n2h4(l), if the percent yield for this reaction is 77.5%, what is the actual mass of hydrazine

Rudiy27

First calculate the moles of N2 and H2 reacted.

moles N2 = 27.7 g / (28 g/mol) = 0.9893 mol

moles H2 = 4.45 g / (2 g/mol) = 2.225 mol

We can see that N2 is the limiting reactant, therefore we base our calculation from that.

Calculating for mass of N2H4 formed:

mass N2H4 = 0.9893 mol N2 * (1 mole N2H4 / 1 mole N2) * 32 g / mol * 0.775

<span>mass N2H4 = 24.53 grams</span>

7 0

2 years ago

The bond dissociation energy to break 4 bond(s) in 1 mole of CH₄ molecules is:_____ **Any help would be greatly appreciated!**

frozen [14]

Answer:

The bond dissociation energy to break 4 bonds in 1 mol of CH is 1644 kJ

Explanation:

Since there are 4 C-H bonds in CH₄, the bond dissociation energy of 1 mol of CH₄ is 4 × bond dissociation energy of one C-H bond.

From the table one mole is C-H bond requires 411 kJ, that is 411 kJ/mol. Therefore, 4 C-H bonds would require 4 × 411 kJ = 1644 kJ

So, the bond dissociation energy to break 4 bonds in 1 mol of CH₄ is 1644 kJ

5 0

2 years ago

The air inside a flexible 3.5L container has a pressure of 115Kpa. What should the volume of the container be increased to in th

LenaWriter [7]

Answer:

V₂ = 4.82 L

Explanation:

Given data:

Initial volume of gas = 3.5 L

Initial pressure = 115 Kpa

Final volume = ?

Final Pressure = 625 torr

Solution:

Final Pressure = 625 torr (625/760 =0.82 atm)

Initial pressure = 115 Kpa (115/101 = 1.13 atm)

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.13 atm × 3.5 L = 0.82 atm × V₂

V₂ = 3.955 atm. L/0.82 atm

V₂ = 4.82 L

5 0

2 years ago

Draw the structure of the major organic product isolated from the reaction of 3-hexyne with hydrogen (1 mol), Lindlar palladium.

ohaa [14]

Answer:

See explanation and image attached

Explanation:

When 1 mole of hydrogen is added to 3-hexyne, the addition occurs on the same face or side of the triple bond to yield cis-2-hexene in the presence of lindlar catalyst which prevents further hydrogenation. This is known as syn addition.

The syn addition is achieved because the hydrogen molecule is first adsorbed on the surface of the palladium metal and is subsequently attached to the same face of the triple bond in 3-hexyne as shown in the image attached to this answer.

6 0

1 year ago

Hexane is a common laboratory solvent and a component of petrol. Its combustion reaction is as follows: 2 C6H14 (9) + 19 02(9) +

Flauer [41]

Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is, $1.01\times 10^3$

Explanation :

The given balanced reaction is,

$2C_6H_{14}(g)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(l)$

Given:

Moles of hexane = 0.121 mol

$\Delta H$ = -8326 kJ/mol

The negative sign indicate that the reaction exothermic or amount of heat released.

As, 1 mole of hexane released heat = 8326 kJ

So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈ $1.01\times 10^3kJ$

Therefore, the heat released by the combustion of 1.121 mol of hexane is $1.01\times 10^3kJ$ .

4 0

2 years ago

A species has the following MO configuration: (σ1s)2(σ1s*)2(σ2s)2(σ2s*)2(σ2p)2(π2p)2. This substance is:_______.

A species has the following MO configuration: (σ1s)2(σ1s)2(σ2s)2(σ2s)2(σ2p)2(π2p)2. This substance is:_______.