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2 years ago

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A survey asked eight people about their wages and educational background. The table shows the hourly wages reported by people wi

th and without a high school diploma. A 2-column table with 4 rows. Column 1 is labeled No high school diploma with entries 10.00, 9.50, 11.50, 13.00. Column 2 is labeled High School Diploma with entries 19.00, 15.25, 14.00, 15.75. Use the information to complete the statements. The mean absolute deviation for people without a high school diploma is . The mean absolute deviation for people with a high school diploma is . The data for people without a high school diploma are more the mean than the data for people with a high school diploma.

2 answers:

svet-max [94.6K]2 years ago

7 0

Answer:The first one is 1.25 the second one is 1.5 ald the 3 one is clustered around

Step-by-step explanation:

it is very easy

olganol [36]2 years ago

5 0

Answer:

1:1.25 2: 1.5 3: clusterd around

Step-by-step explanation:

i am smarte

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An investor believes that investing in domestic and international stocks will give a difference in the mean rate of return. They

arlik [135]

Answer:

So on this case the 90% confidence interval would be given by $-4.137 \leq \mu_1 -\mu_2 \leq 2.087$

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =2.0233$ represent the sample mean 1

$\bar X_2 =3.048$ represent the sample mean 2

n1=15 represent the sample 1 size

n2=15 represent the sample 2 size

$s_1 =4.893387$ population sample deviation for sample 1

$s_2 =5.12399$ population sample deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest at 0.1 of significance so the confidence would be 0.9 or 90%

We want to test:

H0: $\mu_1 = \mu_2$

H1: $\mu_1 \neq \mu_2$

And we can do this using the confidence interval for the difference of means.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =2.0233-3.048=-1.0247$

The degrees of freedom are given by:

$df = n_1 +n_2 -2 = 15+15-2=28$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,28)".And we see that $t_{\alpha/2}=\pm 1.701$

Now we have everything in order to replace into formula (1):

$-1.0247-1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=-4.137$

$-1.0247+1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=2.087$

So on this case the 90% confidence interval would be given by $-4.137 \leq \mu_1 -\mu_2 \leq 2.087$

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

4 0

1 year ago

Brad is hoping to package exactly 48 baseballs together. He sees the side of a box in his storeroom that is 2 x 3. What is he ho

lakkis [162]

The given dimensions of the base of the box are 2 x 3 units.

Let h be the height of the box.

So, the volume of the box = 2 x 3 x h ...(i)

The shape of baseball is spherical and one baseball fits in a cubical box having the minimum dimensions equal to the diameter of the spherical ball.

Assuming the diameter of the baseball is d units.

So, the volume occupied by one baseball= volume of the cubical box having the side $d$ units.

$=d^3$ cubic units

So, the volume required to pack 48 baseballs

$= 48 d^3 \cdots(ii)$

Assuming that all the baseballs fit in the box, i.e peripheral balls in every horizontal and vertical layer touched the box as shown in the figure.

So, the length, 3 units and the width, 2 units, must be the integral multiple of the diameter, $d$ units, of the baseball. i.e

The length, $3 = ad\cdots(iii)$

The width, $2=bd\cdots(iv)$

The height, $h=cd\cdots(iv)$

where $a,b$ and $c$ belong to the natural number.

This required volume must be equals to the volume of the box.

From equations (i) and (ii),

$2\times 3\times h=48d^3$

[from (iii) and (iv)]

$\Rightarrow abhd^2=48d^3$

$\Rightarrow h=\frac{48d^3}{6abd^2}$

$\Rightarrow h=\frac{48}{ab}d$

On comparing with the equation (iv)

$c=\frac{48}{ab}\cdots(v)$

Now, if the diameter of the baseball is unity,i.e, d=1 unit

( integer) and (integer) [from (iii) and (iv)]

(also an integer) [from (v)]

Now, the height of the box,

$h=8 \times 1= 8$ unit.

Hence, the other dimension of the box, is 8 units corrosponding to the unity diameter of the baseball.

Note the height of the box depends on the diameter of the baseball, so it will have infinite possible value for different value of the diameter.

For example, the value of height for d=1 unit has been shown.

and another example may be if units, then (integer) and (integer)

(also an integer) [from (v)]

Now, the height of the box,

$h=2 \times 0.5= 1$ unit. [from (iv)]

Here, the height of the box is 2 units corrosponding to 0.5 unit diameter of the baseball.

The possivle values of d can be taken for which $a,b$ and $c$ must be integers.

6 0

2 years ago

Raj takes a taxi to the airport. He expects the taxi to travel at an average speed of 40 mph. The distance from Raj's house to t

Stells [14]

Answer:

15 minutes more, as 60-45mins = 15 minutes.

Step-by-step explanation:

Distance = 30 miles

Speed = 30mph = 1 hr

Compared to Distance 30 miles

Speed = 40mph = 3/4 of 60mins = 45 mins.

1hr = 60mins = 60-45 = 15 minutes.

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2 years ago

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Chelsea is graphing the function f(x) = 20()x. She begins by plotting the initial value. Which graph represents her first step?

Soloha48 [4]

we have the function

$f(x)=20(\frac{1}{4})^{x}$

we know that

In the equation of the exponential function of the form

$f(x)=a(b)^{x}$

a is the initial value

b is the base

x is the exponent

The initial value is the value of the function when the value of x is equal to zero

in this problem

for $x=0$

$f(0)=20(\frac{1}{4})^{0}$

$f(0)=20(1)=20$

the initial value is the point $(0,20)$

therefore

the answer in the attached figure

6 0

1 year ago

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A forest ranger in the west observation tower spots a fire 41° north of east. Fifteen miles directly east, the forest ranger in

Radda [10]

Draw a horizontal line AB of length 15 miles to represent the positions of the two forest rangers.
Point A is to the left and point B is to the right.
Complete triangle ABC so that m∠A = 41° and m∠B = 56°.
The point C represents the location of the fire.

Let x = length of BC. It is the shortest distance from the forest ranger B to the fire because BC is opposite the smaller angle of 41°.

Because the sum of angles in a triangle is 180°,
m∠C = 180° - (41° + 56°) = 83°.

From the Law of Sines,
x/sin(41) = 15/sin(83)
x = 15*[sin(41)/sin(83)] = 9.915 mi

Answer:
The forest ranger closest to the fire is at a distance of 9.92 miles (nearest hundredth).

5 0

1 year ago

Read 2 more answers