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faust18 [17]
2 years ago
11

A survey asked eight people about their wages and educational background. The table shows the hourly wages reported by people wi

th and without a high school diploma. A 2-column table with 4 rows. Column 1 is labeled No high school diploma with entries 10.00, 9.50, 11.50, 13.00. Column 2 is labeled High School Diploma with entries 19.00, 15.25, 14.00, 15.75. Use the information to complete the statements. The mean absolute deviation for people without a high school diploma is . The mean absolute deviation for people with a high school diploma is . The data for people without a high school diploma are more the mean than the data for people with a high school diploma.
Mathematics
2 answers:
svet-max [94.6K]2 years ago
7 0

Answer:The first one is 1.25 the second one is 1.5 ald the 3 one is clustered around

Step-by-step explanation:

it is very easy

olganol [36]2 years ago
5 0

Answer:

1:1.25      2: 1.5    3: clusterd around

Step-by-step explanation:

i am smarte

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The cost of 8 kg of butter is $ 904. what will be the cost of 14 kg of butter
kvv77 [185]

Answer:

$1582

Step-by-step explanation:

cost of each kg 904/8=113

cost of 14 kg 113x14=1582

the cost of 14 kg of butter is $1582

6 0
2 years ago
Agustina made a scaled copy of the following quadrilateral. She used a scale factor less than 1. What could be the length of the
Leya [2.2K]

Answer:

A

Step-by-step explanation:

8 0
2 years ago
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A group of 85 people were asked whether or not they prefer a bagel or a muffin for breakfast and whether or not they prefer milk
gladu [14]

Answer:

The answer(s) would be WY/WZ, or WYZ (If this is multiple choice)

Step-by-step explanation:

The reasoning is that in the "IRL Equation" the polls showed that orange juice was prefered over milk, and didn't matter whether they wanted a bagel or muffin. All that matters in this equation is that it is one sided (For the 1st poll that is) and now you are able to narrow down the possibilities of the answer(s).

5 0
2 years ago
Suppose that a disk drive has 5,000 cylinders, numbered 0 to 4,999. the drive is currently serving a request at cylinder 2,150,
Anni [7]

Answer:

13011, 7586, 7492 , 7424, 9917, and 9137.

Step-by-step explanation:

(1). FCFS is generally based on what is refer to as first come, first serve. That is to say the first one to come will be treated first so, we have that;

FCFS = 81 + 857 + 1084 + 504 + 2256 + 1074 + 1262 + 1167 + 3442 + 1284 = 13011.

(2). (SSTF) Is all about the shortest distance, for example in this question the shortest distance is =

Thus;

Total distance = (2150 - 2069) + (2296 - 2069) + ( 2296 - 2800) +( 3681 - 2800) + (4965 - 3681) + ( 4965 - 1618) + ( 1618-1523) + ( 1523-1212) + ( 1212-544) + ( 544 - 356).

=81 + 227 + 504 + 881 + 1284 + 3347 + 95 + 311 + 668 + 188 = 7586.

(3).SCAN deals with the processing of the nearest request

The distance =146 + 504 +881 + 1284 + 34(4999-4965) + 2930(4999-2069) + 451 + 95 + 311 + 668 +188 = 7492.

(4). LOOK is just like scan.

The distance = 146 + 504 + 881 + 1284 + 2896 + 451 + 95 + 311 + 668 + 188 = 7424.

(5). C-SCAN: this is the kind of scan from one end to the other.

The distance = 146 + 504 +881 +1284 + 34 (4999 - 4965) + 4999 (4999 -0 )+ 356 (356 -0 )+ 188 + 668 + 311 + 95 + 451 = 9917.

(6). C-LOOK : moves in the following order: 2150, 2296, 2800, 3681, 4965, here head moves back 356, 544, 1212, 1523, 1618, 2069.

Thus;

The distance = 146 + 504 + 881+ 1284 + 4609 (4965 - 356) + 188 + 668 + 311+ 95 + 451 = 9137.

4 0
2 years ago
Annie is creating a stencil for her artwork using a coordinate plane. The beginning of the left edge of the stencil falls at (2,
taurus [48]

Answer:

(A)(12, 9)

Step-by-step explanation:

Given:

The beginning of the left edge of the stencil falls at (2, −1).

A point, say Q on the stencil is at  (4, 1).

Point Q divides the stencil into the ratio 1:4.

We are required to find the end of the stencil.

Mathematically, Point Q divides the stencil internally in the ratio 1:4.

For internal division of a line with beginning point (x_1,y_1) and end point (x_2,y_2) in the ratio m:n, we use the formula

Q(x,y)=(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n} )

(x_1,y_1)=(2, -1), (x_2,y_2)=?, Q(x,y)=(4,1), m:n=1:4

Therefore:

(4,1)=(\dfrac{1x_2+4*2}{1+4} ,\dfrac{1y_2+4*-1}{1+4} )\\(4,1)=(\dfrac{x_2+8}{5} ,\dfrac{y_2-4}{5} )\\$Therefore:\\\dfrac{x_2+8}{5}=4\\x_2+8=4X5\\x_2=20-8=12\\$Similarly\\\dfrac{y_2-4}{5}=1\\y_2-4=5\\y_2=4+5=9\\(x_2,y_2)=(12,9)

The correct option is A.

6 0
2 years ago
Read 2 more answers
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