Answer:
Accuracy = 0.81
Sensitivity = 0.93
Specificity = 0.81
Precision = 0.047
Step-by-step explanation:
Given the confusion matrix :
Actual_______ Donation___ No Donation
Donation______ 268 (TP) _______ 20 (FN)
No Donation ___5375 (FP) _____23439 (TN)
Accuracy is calculated as :
(TP + TN) / (TP+TN+FP+FN)
(268 + 23439) / (268 + 23439 + 5375 + 20)
ACCURACY = (23707 / 29102) = 0.81
Sensitivity (True positive rate) :
TP ÷ (TP + FN)
268 ÷ (268 + 20)
268 ÷ 288 = 0.93
Specificity (True Negative rate) :
TN ÷ (TN + FP)
23439 ÷ (23439 + 5375)
23439 ÷ 28814
= 0.81
Precision :
TP ÷ (TP + FP)
268 ÷ (268 + 5375)
268 ÷ 5643
= 0.047
Answer:
The left side
32
is equal to the right side
32
, which means that the given statement is always true.
True
Step-by-step explanation:
You could rewrite this as double brackets, as you are multiplying together two sets of two terms. It would then look like:
(8i + 6j)(4i + 5j)
and you can expand by multiplying together all of the terms
8i × 4i = 32i²
8i × 5j = 40ij
6j × 4i = 24ij
6j × 5j = 30j²
To get your final answer, you then just need to add together all of the like terms, and get 32i² + 30j² + 64ij
I hope this helps!
<span>width = 90 tan43 degrees = about 84 feet </span>
We assume all employees are either full-time or part-time.
36 = 24 + 12
If the number of full-time employees is 24 or less, the number of part-time employees must be 12 or more. (Thinking, based on knowledge of sums.)
_____
You can write the inequality in two stages.
- First, write and solve an equation for the number of full-time employees in terms of the number of part-time employees.
- Then apply the given constraint on full-time employees. This gives an inequality you can solve for the number of part-time employees.
Let f and p represent the numbers of full-time and part-time employees, respectively.
... f + p = 36 . . . . . . given
... f = 36 - p . . . . . . . subtract p. This is our expression for f in terms of p.
... f ≤ 24 . . . . . . . . . given
... (36 -p) ≤ 24 . . . . substitute for f. Here's your inequality in p.
... 36 - 24 ≤ p . . . . add p-24
... p ≥ 12 . . . . . . . . the solution to the inequality
