The following are the steps the nurse would take to treat the infiltrated site:
1. Stop the infusion and remove the catheter
2. Elevate the extremity
3. Encourage an active range of motion
4. Apply a cold or warm compress depending on the solution infusing
5. Restart the infusion proximal to the location or in another extremity
Now, in order to address hydration requirements of the client, the nurse will have to begin a novel peripheral intravenous in another extremity or to again start the infusion if intravenous access has been created.
<span>Can utilize even low wind speeds to produce electricity.</span>
C is incorrect
Both acids and bases produce ions in solution, are electrolytes, and conduct electricity in solution. Although red litmus is an indicator, it does not change color in an acid, acids are proton donors while bases are proton acceptors. Soaps often contain bases, not acids.
D) conduct electricity in water. is the correct answer
Answer:
Explanation:
<em>The probability of producing plants with white axial flowers would be 1/16.</em>
From the illustration, All F1 individuals had red, axial flowers. It thus means that red and axial genes are dominant over white and terminal genes in the pea plant.
Let us assume that the allele for flower color is A (red) and a (white); and the allele for flower location is B (axial) and b (terminal).
Pure-breeding red, axial flower = AABB
Pure breeding white, terminal flower = aabb
AABB x aabb
F1 genotype = AaBb - all red and axial
At F2:
AaBb x AaBb
Progeny
<em>9 A_B_ red/axial</em>
<em>3 A_bb red/terminal</em>
<em>3 aaB_ white/axial</em>
<em>1 aabb - white/terminal</em>
Hence, the probability of producing plants with white axial flowers in the F2 generation is 1/16.
Answer:
Na+ only
Explanation:
Depolarisation of membrane refers to the change in the resting membrane potential of the membrane of a cell which is usually -70mv to a more positive value.
This value changes when the positive ions move inside the cell which increases the positive charge inside the cell.
In the myocardial cell, the sodium ions move inside the cell which changes the potential towards the more positive side as a result of which the signals for contraction arises.
Thus, Na+ only is correct.
