Question

A vessel containing Ne(g) and Ar(g) has a total pressure of 9.78. If the partial pressure of the Neon (PNe) is 3.78 and the partial pressure of the Argon (PAr) is 6, then the mole-fraction of Ne(g) is _______ and the mole-fraction of Ar(g) is ________.

Answer 1

Answer : The mole fraction of $Ne$ and $Ar$ is, 0.387 and 0.613 respectively.

Explanation :

According to the Dalton's Law, the partial pressure exerted by component 'i' in a gas mixture is equal to the product of the mole fraction of the component and the total pressure.

Formula used :

$p_i=X_i\times p_T$

where,

$p_i$ = partial pressure of gas

$X_i$ = mole fraction of gas

$p_T$ = total pressure of gas

Now we have to determine the partial pressure of $Ne$ and $Ar$

$p_{Ne}=X_{Ne}\times p_T$

Given:

$p_{Ne}=3.78\\\\p_T=9.78$

$3.78=X_{Ne}\times 9.78$

$X_{Ne}=0.387$

and,

$p_{Ar}=X_{Ar}\times p_T$

Given:

$p_{Ar}=6\\\\p_T=9.78$

$6=X_{Ar}\times 9.78$

$X_{Ar}=0.613$

Therefore, the mole fraction of $Ne$ and $Ar$ is, 0.387 and 0.613 respectively.