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devlian [24]
2 years ago
12

Four cups are placed upturned on the counter. each cup has the same number of sweets and a declaration about the number of sweet

s in it. The declaration are: Five or six, seven or eight, six or seven, seven or five. Only one of the declaration is correct. How many sweets are there under each cup?
Mathematics
1 answer:
Mumz [18]2 years ago
4 0

Answer:

6?    i hope this helps some!   :)

Step-by-step explanation:

each has 6 in between the number

5 or 6 p there is a possibility of there being 6

7 or 8 there is at least 6 in this cup

6 or 7 there is at least 6 in this cup

7 or 5 there is a possibility of there being 6

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At a particular restaurant, each onion ring has 45 calories and each chicken wing has 65 calories. A combination meal with onion
IceJOKER [234]

Answer:

Number\ of\ chicken\ rings=5\\\\Number\ of\ onion\ rings=10

Step-by-step explanation:

Let\ number\ of\ chicken\ rings=x\\\\Number\ of\ onion\ rings=Number\ of\ chicken\ rings+5=x+5\\\\

Calories:

Calories\ in\ 1\ chicken\ ring=45\\\\Total\ calories\ because\ of\ onion\ ring=45\times Number\ of\ onion\ ring\\\\Total\ calories\ because\ of\ onion\ ring=45\times(x+5)=45x+225\\\\Calories\ in\ 1\ onion\ ring=65\\\\Total\ calories\ because\ of\ chicken\ ring=65\times Number\ of\ chicken\ ring\\\\Total\ calories\ because\ of\ chicken\ ring=65x\\\\Total\ calories=Calories\ because\ of\ onion\ ring+Calories\ because\ of\ chicken\ ring\\\\Total\ calories=45x+225+65x\\\\Tota\ calories=110x+225

Given\ total\ calories=775\\\\110x+225=775\\\\110x=775-225\\\\110x=550\\\\x=5\\\\Number\ of\ chicken\ rings=5\\\\Number\ of\ onion\ rings=5+5=10

6 0
2 years ago
Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.
TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

So

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

(x-2)\\ (x-3)\\ (x-5)

Part a) Can any of the roots have multiplicity?

The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

For instance, the cubic polynomial function has the zeroes

x=2\\ x=3\\ x=5

each occurring once.

Part b) How can you find a function that has these roots?

To find the cubic polynomial function multiply the factors and equate to zero

so

(x-2)*(x-3)*(x-5)=0\\ (x^{2} -3x-2x+6)*(x-5)=0\\ (x^{2} -5x+6)*(x-5)=0\\ x^{3} -5x^{2} -5x^{2} +25x+6x-30=0\\ x^{3}-10x^{2} +31x-30=0

therefore

the answer Part b) is

the cubic polynomial function is equal to

x^{3}-10x^{2} +31x-30=0

7 0
2 years ago
Read 2 more answers
The weights of cars passing over a bridge have a mean of 3,550 pounds and standard deviation of 870 pounds. Assume that the weig
Annette [7]

Answer:

0.24315

Step-by-step explanation:

Using the z score formula to solve this question

z = (x - μ) / σ,

Such that:

x = raw score

μ = population mean

σ = population standard deviation.

From the question:

x = 3000

μ = 3550

σ = 870

z = (3000 - 3550) / 870

z = -550/870

z = -0.6962

Using the z score table as well as probability calculator(as requested in the question to find the z score)

The probability of having less than 3000 is obtained as:

P(x<3000) = 0.24315

7 0
2 years ago
We know that a triangle with side lengths x2 -1, 2x, and x2 1 is a right triangle. Using those side lengths, find the missing tr
Olenka [21]

Least to greatest, the triples are (2x, x²-1, x²+1). Thus the value in the first column of the table is half the value of the first of the triples. Your completed table will be

\begin{array}{cc}\text{x-value}&\text{triple}\\3&\bf{(6,8,10)}\\\bf{4}&(8,15,17)\\5&\bf{(10,24,26)}\\\bf{6}&(12,35,36)\end{array}

4 0
2 years ago
Can anyone help me with this?
Maurinko [17]

Answer:

D. -6m²n² + 10m²n + 8mn² - 10mn

Step-by-step explanation:

(-7mn + 8mn² - 8m²n²) + (10m²n + 2m²n² - 3mn)

Apply the distributive property to remove the parentheses

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

Combine like terms together and arrange in standard form

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

-8m²n² + 2m²n² + 10m²n + 8mn² - 7mn - 3mn

-6m²n² + 10m²n + 8mn² - 10mn

5 0
2 years ago
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