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2 years ago

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Kaylee has 16 pairs of flip-flops in her closet. She discovers that she has 1 red, 3 blue, 2 brown, 5 black, 1 purple, and 4 pai

rs of pink flip-flops. Assuming she always replaces them, what is the probability that she will choose a blue pair on Monday and a pink pair on Tuesday?

1 answer:

Natalija [7]2 years ago

4 0

Answer:3/16 and 4/16

Step-by-step explanation:

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Please help me with this math question

earnstyle [38]

80.64
because 16 times 12 is 192
if every tile is 2 feet divide 192 by 2
you should get 96 meaning there are 96 tiles
then take 96 and multiply by it by .84 because every tile is 84 cents
you then get 80.64

6 0

2 years ago

Find the length of the third side of the right triangle.

lara31 [8.8K]

Answer: you can use Pythagorean theorem , which formula is $a^{2} + b^{2} =c^{2}$ , "a" and "b" are the sides, and "c" is the hypotenuse (the longest side, the side opposite to the 90 degree angle)

<em>Example:</em>

If they give that one side is 2 inches and the other side is 4 and you need to find the hypotenuse it would be like this:

1) plug the numbers to the formula

$4^2 + 6^2 = c^{2}$

2) solve the exponents of the numbers given (not the letter, in this case "c")

16 + 36 = $c^2$

3) combine like terms (in this case 16 +36)

52 = $c^2$

4) Finally, Find the square root of "c" to remove its exponent and do the same to the other side, in this case 52)

$\sqrt{52} = \sqrt{c}$

(square root of 52 rounded to the nearest hundred is 7.21)

7.21 = c

<h3><u><em>So 7.21 is your missing side in this example</em></u></h3><h3>look up Pythagorean theorem Khan Academy</h3>

8 0

2 years ago

In a small community, a survey on the favorite television programs of 63 housewives was made. Based on the survey, 38 housewives

scoundrel [369]

Answer:

x = 4

Step-by-step explanation:

3 0

2 years ago

The following exercise refers to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a ca

dem82 [27]

Answer:

$\frac{4}{663}$

Step-by-step explanation:

Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.

A - the first card is 4

B - second card is ace

We have to find probability for

$A\bigcap B$

P(A) = no of 4s in the deck/total cards = $\frac{4}{52} =\frac{1}{13}$

After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it

P(B) = no of Aces in 51 cards/51 = $\frac{4}{51}$

Hence

$P(A\bigcap B) = \frac{1}{13} *\frac{4}{51} \\=\frac{4}{663}$

(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)

8 0

2 years ago

Read 2 more answers

Suppose babies born in a large hospital have a mean weight of 4095 grams, and a standard deviation of 569 grams. If 130 babies a

Butoxors [25]

Answer:

$P =0.3998$

Step-by-step explanation:

Let ${\overline{x}}$ be the average of the sample, and the population mean will be $\mu$

We know that:

$\mu = 4095$ gr

Let $\sigma$ be the standard deviation and n the sample size, then we know that the standard error of the sample is:

$E=\frac{\sigma}{\sqrt{n}}$

Where

$\sigma=569$

$n=130$

In this case we are looking for:

$P(|{\displaystyle{\overline{x}}}- \mu|>42)$

This is:

${\displaystyle{\overline{x}}}- \mu>42$ or ${\displaystyle{\overline{x}}}- \mu$

$P=P({\displaystyle{\overline{x}}}- \mu>42)+ P({\displaystyle{\overline{x}}}- \mu$

Now we get the z score

$Z=\frac{{\displaystyle{\overline{x}}}-\mu}{\frac{\sigma}{\sqrt{n}}}$

$P=P(z>\frac{42}{\frac{569}{\sqrt{130}}}) + P(z$

$P=P(z>0.8416) + P(z$

Looking at the tables for the standard nominal distribution we get

$P =0.1999+0.1999$

$P =0.3998$

6 0

2 years ago