Question

There were 230{,}600230,600230, comma, 600 jobs available in the field of radiology in the year 201420142014. Each year, that number is expected to grow by 0.9\%0.9%0, point, 9, percent. Write a function that gives the expected number j(t)j(t)j, left parenthesis, t, right parenthesis of jobs in radiology t years from the year 201420142014.

Answer 1

Answer:

The expected number of jobs is given by the function

$j(t)=230600(1.009)^t$

Step-by-step explanation:

Given that, there were 230,600 jobs available in the field radiology in the year 2014 and the grow at a rate 0.9% each year.

This is a exponential growth.

Exponential grow function:

$P(t)= P_0(1+r)^t$

P(t)= Amount after t years

$P_0$ = The initial amount

r= rate of grow

t = Time in year.

Here P(t)= j(t), $P_0$ = 230,600,  r=0.9%=0.009,  t=t

The expected number of jobs is given by the function

$j(t)=230600(1+0.009)^t$

$\Rightarrow j(t)=230600(1.009)^t$

Answer 2

Answer:

j(t)=230600(1.009)^t

Step-by-step explanation: