Answer:
0.659 is the probability that a tutor charges between $10 and $20 per hour.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = $15 per hour
Standard Deviation, σ = $5.25 per hour
We are given that the distribution of tutoring prices is a bell shaped distribution that is a normal distribution.
Formula:
P( tutor charges between $10 and $20 per hour)
0.659 is the probability that a tutor charges between $10 and $20 per hour.
Answer:
Ordering a soft drink is independent of ordering a square pizza.
Step-by-step explanation:
20% more customers order a soft drink than pizza, therefore they cannot be intertwined.
Given: P(A)=0.5 & P(B)=.7
P(A∩B) = P(A) × P(B)
= 0.5 × .7
= 0.35
P(A∪B) = P(A) + P(B) - P(A∩B)
= 0.5 + .7 - 0.35
= 0.85
P(AΔB) = P(A) + P(B) - 2P(A∩B)
= 0.5 + .7 - 2×0.35
= 0.5
P(A') = 1 - P(A)
= 1 - 0.5
= 0.5
P(B') = 1 - P(B)
= 1 - .7
= 0.3
P((A∪B)') = 1 - P(A∪B)
= 1 - 0.85
= 0.15
What figure? anyways if it is a square you simply square root the area. EX: A=81 S=9
it it is a rectangle, you must know the other side before dividing
and so on
sorry I couldn't see the figure
Fixed costs:
$350 + $120 + $170 = $640
Variable costs:
x * ( $6.50 + $3.64 ) = x * 10.14
Sales income ( total ):
x * $36.40
FC + FV - Income = 0
640 + 10.14 x - 36.40 x = 0
640 - 26.26 x = 0
26.26 x = 640
x = 640 : 26.26 = 24.37
Answer:
The minimum number of passengers needed per cruise, so that the cruise company can be sure it will make a profit is 25.
Answer:
The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.
Step-by-step explanation:
Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.
Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.
Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,
3f + 2.6 = 3.1 + 2.6 = 3 + 2.6 = 5.6
2f + 2.6 = 2.1 + 2.6 = 2 + 2.6 = 4.6
5.6 = 4.6
Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.
3f + 2.6 = 2f + 2.6
3f = 2f
3f - 2f = 0
f = 0
This is true only when f=0.
Hence,
The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.
