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ANEK [815]
2 years ago
11

The products of combustion from a burner are routed to an industrial application through a thin-walled metallic duct of diameter

Di=1 m and length L=100 m. The gas enters the duct at atmospheric pressure and a mean temperature and velocity of Tm,i=1600 K and Um,i=10 m/s, respectively. It must exit the duct at a temperature that is no less than Tm,o=1400 K. What is the minimum thickness of an alumina-silica insulation (Kins=0.125 W/m*K) needed to meet the outlet requirement under worst case conditions for which the duct is exposed to ambient air at T[infinity]=250 K and a cross-flow velocity of V=15 m/s? The properties of the gas may be approximated as those of air, and as a first estimate, the effect of the insulation thickness on the convection coefficient and the thermal resistance associated with the cross flow may be neglected.

Engineering
1 answer:
Marysya12 [62]2 years ago
6 0

Answer:

0.11m

Explanation:

Thermal resistance can be rightly defined as a heat property and a measurement of a temperature difference by which an object or material resists a heat flow.

Please for the detailed step by step solution of the given problem, check the attached file.

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Twenty distinct cars park in the same parking lot every day. Ten of these cars are US-made, while the other ten are foreign-made
Zina [86]

Answer:

Total no. of ways to line up cars is 20! = 2.43 c 10^18

Probability that the cars alternate is 0.00001 or 0.001%

Explanation:

Since, the position of a car is random.Therefore, number ways in which cars can line up is given as:

<u>No. of ways = 20! = 2.43 x 10^18</u>

For the probability that cars alternate, two groups will be formed, one consisting of US-made 10 cars and other containing 10 foreign made. The number of favorable outcomes for this can be found out as the arrangements of 2! between these groups multiplied by the arrangements of 10! for each group, due to the arrangements among the groups themselves.

Favorable Outcomes = 2! x 10! x 10!

Thus the probability of event will be:

Probability = Favorable Outcomes/Total No. of Ways

Probability = (2! x 10! x 10!)/20!

<u>Probability = 0.00001 = 0.001%</u>

4 0
2 years ago
Air enters a nozzle steadily at 280 kPa and 77°C with a velocity of 50 m/s and exits at 85 kPa and 320 m/s. The heat losses from
Arlecino [84]

The input values are the following

\left.T_{1}=350 K\right\ then

h_{1}=350.49 \frac{k j}{k g}, s_{1}=1.85708 \frac{K j}{K g \cdot K}

By using the energy equilibrium

\dot{E}_{i n}-\dot{E}_{o u t}=\Delta \dot{E}_{s y s t e m}=0 , \dot{E}_{i n}=\dot{E}_{o u t}

we haveT_{2}=297.2 K

eq (1)  \dot{m}\left(h_{1}+\frac{V_{1}^{2}}{2}\right)=\dot{m}\left(h_{2}+\frac{V_{2}^{2}}{2}\right)+\dot{Q}_{o u t} ∴

0=q+h_{2}-h_{1}+\frac{V_{2}^{2}-V_{1}^{2}}{2}

Now, for specific energy h2:

h_{2}=h_{1}-q_{o u t}-\frac{V_{2}^{2}-V_{1}^{2}}{2}

By replacing the eq (1) we have

h_{2}=350.49 \frac{k j}{k g}-3.2-\frac{\left(320 \frac{m}{s}\right)^{2}-\left(50 \frac{m}{m}\right)^{2}}{2}\left(\frac{1 \frac{k j}{k g}}{1000 \frac{m^{2}}{s^{2}}}\right)

h_{2}=297.34 \frac{k j}{k g}

By using a standard ideal-gas properties of air we have

T_{2}=297.2 K

6 0
2 years ago
A 20-centimeter wrench is used to loosen a bolt. The force is applied 0.20m from the bolt. It takes 50 newtons to loosen the bol
defon

Answer:

The force would be 57.8 N if it was applied at a 30-degree angle from perpendicular.

Explanation:

We know that torque and force are represented by the following equation

τ =  r x F sinθ ---- (1)

where τ is Torque, r is radius, F is force and θ is the angle between the force and lever arm.

Given data:

F = 50 N

r = 0.2 m

we have to find the force when θ = 30°

Putting these values in equation 1, we get

τ  = 0.2 x 50 x sin(90°)

τ  = 10 Nm

so Torque is 10 Nm

Now we will calculate the force was applied at a 30 degree angle from perpendicular, in this case the equation 1 becomes as

τ =  r x F cosθ

Putting the values of τ , r, θ  and F in above equation

10 = 0.2 x F x cos(30°)

Rearranging the above equation

F = 10 / (0.2 x cos (30°))

F = 10 / 0.173

F = 57.8 N

8 0
2 years ago
A horizontal steel pipe having a diameter of 5 cm is maintained at a temperature of 50oC in a large room where the air (h = 6.5
11Alexandr11 [23.1K]

Answer:

55.67W/m

Explanation:

Attached is the full solution.

6 0
2 years ago
Only put coolant into your radiator when the engine is _____.
Arada [10]

Only put ciilant into ur radiator when the engine is cool (D)

5 0
2 years ago
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