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Viktor [21]
2 years ago
6

Dylan wanted to find the average number of hours per day that the students in his class practiced their instruments. He chose th

ree students by drawing their names from a hat. What should he do to ensure that he has an accurate average for the class?
A dot plot going from 0 to 4. There is 1 dot above 0, 1 dot above 0.5, and 1 dot above 4.
He should add the three numbers and divide by 3 because that is how one finds an average.
He should poll more students to eliminate the variability caused by a sample size that is too small.
He should take the middle number as his average since he has three observations.
He should just find the average of 0.5 and 4 since 0 does not change anything when adding.
Mathematics
2 answers:
aev [14]2 years ago
8 0

Answer:

D

Step-by-step explanation:

hope I was correct

Contact [7]2 years ago
7 0

Answer:

I chose D cause i did the test

Step-by-step explanation:

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The probability that a person in the United States has type B​+ blood is 12​%. Three unrelated people in the United States are s
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Answer:

The probability that all three have type B​+ blood is 0.001728

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a person in the United States has type B​+ blood is 12​%.

This means that p = 0.12

Three unrelated people in the United States are selected at random.

This means that n = 3

Find the probability that all three have type B​+ blood.

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.12)^{3}.(0.88)^{0} = 0.001728

The probability that all three have type B​+ blood is 0.001728

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Express the null hypothesis and the alternative hypothesis in symbolic form. The owner of a football team claims that the averag
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Answer:

H0: μ ≤ 68,800

H1: μ > 68,800

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (H1) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above;

The Null hypothesis is that the average attendance at games is less than or equal to 68,800.

H0: μ ≤ 68,800

The alternative hypothesis is that the average attendance at games is over 68,800.

H1: μ > 68,800

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2 years ago
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