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Free_Kalibri [48]
2 years ago
5

Write a quadratic function f whose zeros are 6 and 1

Mathematics
1 answer:
Ratling [72]2 years ago
4 0

Answer:

x^2-7x+6

Step-by-step explanation:

(x-6)(x-1)

x^2-1x-6x+6

x^2-7x+6

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A quality control engineer tests the quality of produced computers. suppose that 5% of computers have defects, and defects occur
11111nata11111 [884]
(a) 0.059582148 probability of exactly 3 defective out of 20

 (b) 0.98598125 probability that at least 5 need to be tested to find 2 defective.

  (a) For exactly 3 defective computers, we need to find the calculate the probability of 3 defective computers with 17 good computers, and then multiply by the number of ways we could arrange those computers. So

 0.05^3 * (1 - 0.05)^(20-3) * 20! / (3!(20-3)!)

 = 0.05^3 * 0.95^17 * 20! / (3!17!)

 = 0.05^3 * 0.95^17 * 20*19*18*17! / (3!17!)

 = 0.05^3 * 0.95^17 * 20*19*18 / (1*2*3)

 = 0.05^3 * 0.95^17 * 20*19*(2*3*3) / (2*3)

 = 0.05^3 * 0.95^17 * 20*19*3

 = 0.000125* 0.418120335 * 1140

 = 0.059582148

  (b) For this problem, let's recast the problem into "What's the probability of having only 0 or 1 defective computers out of 4?" After all, if at most 1 defective computers have been found, then a fifth computer would need to be tested in order to attempt to find another defective computer. So the probability of getting 0 defective computers out of 4 is (1-0.05)^4 = 0.95^4 = 0.81450625.

 The probability of getting exactly 1 defective computer out of 4 is 0.05*(1-0.05)^3*4!/(1!(4-1)!)

 = 0.05*0.95^3*24/(1!3!)

 = 0.05*0.857375*24/6

 = 0.171475

 
 So the probability of getting only 0 or 1 defective computers out of the 1st 4 is 0.81450625 + 0.171475 = 0.98598125 which is also the probability that at least 5 computers need to be tested.
3 0
2 years ago
An orange is shot up into the air with a catapult. The function h given by h(t)=15+60t-16t^2 models the orange’s height, in feet
Studentka2010 [4]

Complete question is:An orange is shot up into the air with a catapult. The function h given by h(t) = 15 + 60t - 16t² models the orange’s height, in feet, t seconds after it was launched.

Select all the true statements about the situation.

Options:

1. The domain of function h only contains values greater than or equal to 0.

2. The orange is at the same height 1 second after launch and 2 seconds after launch.

3. After 3 seconds, the orange has hit the ground.

4. The orange is 15 feet above the ground when it is launched.

5. The value t = 10 does not belong to the domain of h.

Answer:

Option 1 - True

Option 2 - False

Option 3 - False

Option 4 - True

Option 5 - True

Step-by-step explanation:

Looking at the options,

-The domain is the x or t value and it is time. Now, time can only be positive or greater than or equal to zero i.e. t ≥ 0. Thus, option 1 is true.

- At t = 1 second;

h = 15 + 60(1) - 16(1)²

h = 15 + 60 - 16 = 59 ft

Also, at t = 2 seconds;

h = 15 + 60(2) - 16(2)²

h = 15 + 120 - 64 = 71 ft

So,value of h is not the same at t = 1 and t = 2. Thus, option 2 is not true.

- The orange will hit the ground when h(t) = 0.

However, at t = 3;

h(t) = 15 + 60(3) - 16(3)²

h(t) = 51 ft

h(t) is not equal to zero at t = 3, so option 3 is false

- when the orange is launched it is at time t = 0.

Thus,

h(0) = 15 + 60(0) - 16(0)²

h(0) = 15 ft

So option 4 is true.

- At t=10, h(t) = 15 + 60(10) - 16(10)²

h(10) = -985

This means the orange would be below ground level and thus doesn't belong to the domain of h, so option 5 is true.

6 0
2 years ago
Write 3.01 (1 repeating) as a mixed fraction?
Advocard [28]

Answer:

3 1/100

Step-by-step explanation:

4 0
2 years ago
∠A and ∠C are right angles. m∠p = degrees.
almond37 [142]
M<P 59° is your answer
6 0
2 years ago
Read 2 more answers
What’s the answer????
alex41 [277]

Answer:

80

Step-by-step explanation:

the formula is base times height the height is 10 and the base is 8 so 10 times 8 equals 80

4 0
2 years ago
Read 2 more answers
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