answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
larisa [96]
2 years ago
7

You are stranded on a deserted island with 100 m of 18 gauge insulated copper wire, a light bulb rated at 3.0 V, a 50 V battery,

a large iron nail, a few simple tools (including wire cutters), and your clothes. There are of course trees, rocks, sand, and other assorted island flora and fauna. (The island is a bit unique: there is a dampening field present that inhibits fire.) Since you have been stranded on the island, each night after dark a helicopter flies over.
Using the materials at hand, describe a way to get yourself rescued. (You must support your description by including brief references to any laws or equations that apply.)
Physics
2 answers:
Akimi4 [234]2 years ago
7 0

Answer:

One can get rescued by sending SOS signals in both day and night time as explained as follows

Explanation:

To answer the question, we note that

During the day

Since the we have sand rocks and sand therefore we can inscribe SOS on the sand

We can also use the rocks to build three X marks in a trangular pattern signalling SOS

At night

1. Crete a pulsating light to attract the Helicopter

To do that we can wrap the copper wire into a coil, connect it to the 3.0 V  bulb and the 50 V battery

The current through the coil reduces and increases as the large iron nail slides in and out of the coil making the light to dim and brighten such that it is pulsating.

The equation for the current through the coil is given as follows;

Current, \ I  = \frac{Voltage}{Impedance}

Where:

Impedance = \bar Z = R +j·X

The X varies as the large nail moves in the coil.

2. SOS signal

The SOS signal can also be made directly by turning the bulb on and off using three short flashes followed by three long flashes and then three short flashes which can be effected by either completing and disconnecting the electric bulb, copper wire and 50 V battery directly as described or by covering the constantly lit bulb with the clothes sequentially.

 

Alexxx [7]2 years ago
6 0

Explanation:

Since the person has a copper wire, light the bulb and a battery. In order to show his mark during night, he would light the bulb.

For that he would be making two wires. Connect one wire with the negative end of the battery and connect the other end of wire with the base of the bulb. Connect the other wire to the positive end of the battery and to the base of the bulb. This would complete the circuit to light the bulb.

Now since battery needs to charged also, he will use the copper wire and iron nail. When he will move iron nail quickly through a coil of copper wire, electricity will be produced that would be used to charge the battery.

You might be interested in
Noise-canceling headphones are an application of destructive interference. Each side of the headphones uses a microphone to pick
jeka57 [31]

Answer:

2.5 ms

Explanation:

v = Speed of sound in air = 343 m/s

f = Frequency = 200 Hz

Wavelength is given by

\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{343}{200}\\\Rightarrow \lambda=1.715\ m

In the case of destructive interference, path difference is given by

x=\dfrac{\lambda}{2}\\\Rightarrow x=\dfrac{1.715}{2}\\\Rightarrow x=0.8575\ m

Delay is givenn by

t=\dfrac{x}{v}\\\Rightarrow t=\dfrac{0.8575}{343}\\\Rightarrow t=0.0025\ s

The minimum headphone delay, that will cancel this noise is 2.5 ms

6 0
2 years ago
The first-order rearrangement of CH3NC is measured to have a rate constant of 3.61 × 10–15 s–1 at 298 K and a rate constant of 8
netineya [11]

Answer:

The activation energy for this reaction, Ea = 159.98 kJ/mol

Explanation:

Using the Arrhenius equation as:

ln\frac {K_2}{K_1}=-\frac {E_a}{R}\times (\frac {1}{T_2}-\frac {1}{T_1})

Where, Ea is the activation energy.

R is the gas constant having value 8.314 J/K.mol

K₂ and K₁ are the rate constants

T₂ and T₁ are the temperature values in kelvin.

Given:

K₂ = 8.66×10⁻⁷ s⁻¹ , T₂ = 425 K

K₁ = 3.61×10⁻¹⁵ s⁻¹ , T₁ = 298 K

Applying in the equation as:

ln\frac {8.66\times 10^{-7}}{3.61\times 10^{-15}}=-\frac {E_a}{8.314}\times (\frac {1}{425}-\frac {1}{298})

Solving for Ea as:

Ea = 159982.23 J /mol

1 J/mol = 10⁻³ kJ/mol

Ea = 159.98 kJ/mol

7 0
2 years ago
A visitor to the observation deck of a skyscraper manages to drop a penny over the edge. As the penny falls faster, the force du
pentagon [3]
If a coin is dropped at a relatively low altitude, it's acceleration remains constant. However, if the coin is dropped at a very high altitude, air resistance will have a significant effect. The initial acceleration of the coin will be the greatest. As it falls down, air resistance will counteract the weight of the coin. So, the acceleration will decrease. Although the acceleration decreases, the coin still accelerates, that is why it falls faster. When the air resistance fully counters the weight of the coin, the acceleration will become zero and the coin will fall at a constant speed (terminal velocity). So, the answer should be, The acceleration decreases until it reaches 0. The closest answer is.
a. The acceleration decreases.
8 0
2 years ago
Read 2 more answers
A point charge q1 = 4.50 nC is located on the x-axis at x = 1.95 m , and a second point charge q2 = -6.80 nC is on the y-axis at
Vinvika [58]

Answer:

Explanation:

One charge is situated at x = 1.95 m . Second charge is situated at y = 1.00 m

These two charges are situated outside sphere as it has radius of .365 m with center at origin. So charge inside sphere = zero.

Applying Gauss's theorem

Flux through spherical surface = charge inside sphere / ε₀

= 0 / ε₀

= 0 Ans .

3 0
2 years ago
Un tubo de acero de 40000 kilómetros forma un anillo que se ajusta bien a la circunferencia de la tierra. Imagine que las person
Darina [25.2K]

Answer:

82.76m

Explanation:

In order to find the distance of the steel ring to the ground, when its temperature has raised by 1°C, you first calculate the radius of the steel tube before its temperature increases.

You use the formula for the circumference of the steel ring:

C=2\pi r    (1)

C: circumference of the ring = 40000 km = 4*10^7m (you assume the circumference is the length of the steel tube)

you solve for r in the equation (1):

r=\frac{C}{2\pi}=\frac{4*10^7m}{2\pi}=6,366,197.724m

Next, you use the following formula to calculate the change in the length of the tube, when its temperature increases by 1°C:

L=Lo[1+\alpha \Delta T]         (2)

L: final length of the tube = ?

Lo: initial length of the tube = 4*10^7m

ΔT = change in the temperature of the steel tube = 1°C

α: thermal coefficient expansion of steel = 13*10^-6 /°C

You replace the values of the parameters in the equation (2):

L=(4*10^7m)(1+(13*10^{-6}/ \°C)(1\°C))=40,000,520m

With the new length of the tube, you can calculate the radius of a ring formed with the tube. You again solve the equation (1) for r:

r'=\frac{C}{2\pi}=\frac{40,000,520m}{2\pi}=6,366,280.484m

Finally, you compare both r and r' radius:

r' - r = 6,366,280.484m - 6,366,197.724m = 82.76m

Hence, the distance to the ring from the ground is 82.76m

4 0
2 years ago
Other questions:
  • Lorenzo is making a prediction. “I learned that nonmetals increase in reactivity when moving from left to right. So I predict th
    12·2 answers
  • A piece of candy has 5 calories (or 5000 calories). if it could be burned, leaving nothing but carbon dioxide and water, how muc
    8·2 answers
  • The image shows positions of the earth and the moon in which region would an astronaut feel the lightest
    10·2 answers
  • The energy difference between the 5d and the 6s sublevels in gold accounts for its color. If this energy difference is about 2.7
    6·1 answer
  • Calculate the partial pressure of ozone at 441 ppb if the atmospheric pressure is 0.67 atm.
    6·1 answer
  • A block weighing 400 kg rests on a horizontal surface and supports on top of it ,another block of weight 100 kg which is attache
    10·1 answer
  • Feng and Isaac are riding on a merry-ground. Feng rides on a horse at the outer rim of the circular platform, twice as far from
    10·1 answer
  • The dielectric strength of rutile is 6.0 × 106 V/m, which corresponds to the maximum electric field that the dielectric can sust
    13·2 answers
  • There are lots of examples of ideal gases in the universe, and they exist in many different conditions. In this problem we will
    8·1 answer
  • An unusual lightning strike has a vertical portion with a current of –400 A downwards. The Earth’s magnetic field at that locati
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!