Question:
What are the solution(s) to the quadratic equation 50 – x2 = 0?
A) x = ±2Plus or minus 2 StartRoot 5 EndRoot
B) x = ±6Plus or minus 6 StartRoot 3 EndRoot
C) x = ±5Plus or minus 5 StartRoot 2 EndRoot
D) no real solution
Answer:
C) x = ±5Plus or minus 5 StartRoot 2 EndRoot
Answer:
probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.
Step-by-step explanation:
"Find the probability that a student chosen at random from those who play a sport does not watch rugby."
90-15= 75 students either play a sport OR watch rugby
65+71-75=
136-75=
61 people play a sport AND watches rugby
14 people play a sport and DOES NOT watch rugby
is the probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.
Let x = width
x+1 is then the length
2x+2(x+1)=66
2x+2x+2=66
4x=64
x=16
deck will be 16x17, nice for a BBQ. :)
Answer:
The answer is 23 years.
Step-by-step explanation:
We will use the formula :
Here P = 220
r = 3%
A = 400
Putting these values in the formula we get,
Taking log on both sides,
ln(1.03)t=ln 2
t=23.44 or rounding to nearest, t=23 years
The graph of the function can be shown as below.
Answer:
a.0.8664
b. 0.23753
c. 0.15866
Step-by-step explanation:
The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between
a. N164.50 and N185.50?
b. greater than N180.00?
c. less than N168.00?
We solve the above question using z score formula
z = (x-μ)/σ/√n where
x is the raw score,
μ is the population mean = N175
σ is the population standard deviation = N42
n is random number of sample = 36
a. Between N164.50 and N185.50?
For x = N 164.50
z = 164.50 - 175/42 /√36
z = -1.5
Probability value from Z-Table:
P(x = 164.50) = 0.066807
For x = N185.50
z = 185.50 - 175/42 /√36
z =1.5
Probability value from Z-Table:
P(x=185.50) = 0.93319
Hence:
P(x = 185.50) - P(x =164.50)
= 0.93319 - 0.066807
= 0.866383
Approximately = 0.8664
b. greater than N180.00?
x > N 180
Hence:
z = 180 - 175/42 /√36
z = 5/42/6
z = 5/7
= 0.71429
Probability value from Z-Table:
P(x<180) = 0.76247
P(x>180) = 1 - P(x<180) = 0.23753
c. less than N168.00?
x < N168.
z = 168 - 175/42 /√36
z = -7/42/6
z = -7/7
z = -1
Probability value from Z-Table:
P(x<168) = 0.15866
