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Andreyy89
2 years ago
9

What is the remainder in the synthetic division problem below?

Mathematics
1 answer:
Zepler [3.9K]2 years ago
5 0

Answer:

<h2>D.8</h2>

Step-by-step explanation:

The synthetic division is

   |      4     6    -2

1   |             4    10

          4     10    8

As you can observe, the remainder in the given synthetic division is 8, because that's the ultimate result.

Therefore, the right answer is D.8

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Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random
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Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes P_B(A).

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
P(A|B)= \frac{P(A \cap B)}{P(B)}

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is \frac{1}{3}

Part A:
To find <span>the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}

</span><span>P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

</span><span>Thus P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}

Therefore, P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}


Part B:
</span>To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime<span>, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.
</span><span>
P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}

</span><span>P(D)= \frac{1}{3}</span><span>

Therefore, P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}</span>
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2 years ago
Alexa buys 27 stamps, each stamp is of 1 square unit of area. She exchanges them for 8 sugar cubes, whose total volume is numeri
Vikentia [17]
The answer is 8 sugar cubes
8 0
2 years ago
If five friends want to share 1.25 of a pizza evenly how much pizza would each person get
Amanda [17]

1.25 /5

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25/5 = 5

2 numbers

1.25 /5 = .25

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4 0
2 years ago
Read 2 more answers
The angle measures associated with which set of ordered pairs share the same reference angle
Trava [24]

Answer:

Option 3 is right.

Step-by-step explanation:

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In whatever way we find reference angles,

cos will remain cos only and sin will remain sin only there may be only changes in sign.

Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos.  Hence these options cannot be for reference angles.

III option is (-\frac{1}{2} ,\frac{-\sqrt{3} }{2} )(\frac{1}{2} ,\frac{\sqrt{3} }{2} )

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ie reference angle of orignal angle t = 180+t

SO this option is right.

7 0
1 year ago
Read 2 more answers
A rectangular pool 18 meters by 12 meters is surrounded by a walkway of width x
vesna_86 [32]

Answer:

x=3 meters

Step-by-step explanation:

step 1

Find the area of the rectangular pool

A=LW

we have

L=18\ m\\W=12\ m

substitute

A=18(12)=216\ m^2

step 2

Find the area of rectangular pool including the area of the walkway

Let

x ----> the width of the walkway

we have

L=(18+2x)\ m\\W=(12+2x)\ m

substitute

A=(18+2x)(12+2x)

step 3

Find the area of the walkway

To find out the area of the walkway subtract the area of the pool from the area of rectangular pool including the area of the walkway

so

A=(18+2x)(12+2x)-216

step 4

Find the value of x if the area of the walkway equal the area of the pool

so

(18+2x)(12+2x)-216=216

Solve for x

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Solve the quadratic equation by graphing

The solution is x=3 meters

see the attached figure

8 0
2 years ago
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