Solution:
x y ║ z w→→Given
Also, x z is a transversal, that intercepts x y and z w.
So, ∠ x z w=∠z x y→→Alternate interior angles as, x y ║ z w.
Also, v is point of intersection of x z and y w.
∠ x v y ≅ ∠ z v w→→[ Vertically opposite angles]
So,→→ Δ x y v ~ Δ z w v⇒⇒[Angle-Angle Similarity]
Answer:
10$ an hour
Step-by-step explanation:
1/2c=6-1
c=2(6-1)
c=10
Answer:
Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.
Step-by-step explanation:
Consider the provided information.
The mean number (per group) who recognize the Yummy brand name is 12.5, and the standard deviation is 0.58.
Mean = μ= 12.5
σ = 0.58
n = 15
![\mu\pm2\sigma=12.5\pm 2(0.58)\\\mu\pm2\sigma=12.5\pm1.16\\\mu\pm2\sigma=[11.34, 13.66]](https://tex.z-dn.net/?f=%5Cmu%5Cpm2%5Csigma%3D12.5%5Cpm%202%280.58%29%5C%5C%5Cmu%5Cpm2%5Csigma%3D12.5%5Cpm1.16%5C%5C%5Cmu%5Cpm2%5Csigma%3D%5B11.34%2C%2013.66%5D)
Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.
Answer:
the answer here is C) translation, then reflection
Step-by-step explanation:
if you translate point P to point R and then translate across that point they map onto each other
Answer:
1131 pounds.
Step-by-step explanation:
We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.
First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:


The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.


Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.



Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.