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kvv77 [185]
2 years ago
8

Find the value of z such that 0.9722 of the area lies between −z and z. Round your answer to two decimal places.

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
7 0

Answer:

-2.20 < z < 2.20

Step-by-step explanation:

You are saying the entire area = 0.9722

so    1 - 0.9722 = 0.0278

then  we want it to fit in the middle of the normal curve with center 0

so...

0.0278/2 =0.0139  this corresponds to 2.20  on the z-score chart

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Solution:

x y ║ z w→→Given

Also, x z is a transversal, that intercepts x y and z w.

So, ∠ x z w=∠z x y→→Alternate interior angles as, x y ║ z w.

Also, v is point of intersection of x z and y w.

∠ x v y ≅ ∠ z v w→→[ Vertically opposite angles]

So,→→ Δ x y v ~ Δ z w v⇒⇒[Angle-Angle Similarity]




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For each hour he babysits, Anderson earns $1 more than half of Carey’s hourly rate. Anderson earns $6 per hour. Which equation c
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10$ an hour

Step-by-step explanation:

1/2c=6-1

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Focus groups of 15 people are randomly selected to discuss products of the Yummy Company. It is determined that the mean number
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Answer:

Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.

Step-by-step explanation:

Consider the provided information.

The mean number (per group) who recognize the Yummy brand name is 12.5, and the standard deviation is 0.58.

Mean = μ= 12.5  

σ = 0.58

n = 15

\mu\pm2\sigma=12.5\pm 2(0.58)\\\mu\pm2\sigma=12.5\pm1.16\\\mu\pm2\sigma=[11.34, 13.66]

Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.

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The triangles are congruent by the SSS congruence theorem. Which rigid transformation(s) can map MNP onto TSR? Reflection only r
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An unloaded truck and trailer, with the driver aboard, weighs 30{,}00030,00030, comma, 000 pounds. When fully loaded, the truck
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Answer:

1131 pounds.

Step-by-step explanation:

We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.

First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:

\text{Weight of tires of the fully loaded semi-truck}=18\times 3,300

\text{Weight of tires of the fully loaded semi-truck}=59,400

The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.

\text{Weight of 26 pallets of cargo}=59,400-30,000

\text{Weight of 26 pallets of cargo}=29,400

Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.

\text{Average weight of one pallet of cargo}=\frac{29,400}{26}

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Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.

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2 years ago
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