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9966 [12]
2 years ago
15

A sequence of transformations which moves ΔFGH onto ΔIJK shows that ΔFGH ≅ ΔIJK. Which part of the triangles are congruent by CP

CTC?
A) IJ ≅ FH
B) GH ≅ JK
C) FG ≅ JK
D) IK ≅ GH
PLZ HELPP‼️‼️‼️‼️
Mathematics
1 answer:
Fudgin [204]2 years ago
6 0

Answer:

B) GH ≅ JK

Step-by-step explanation:

From the names of the triangles, it is deduced that sides FG and IJ are corresponding parts, sides GH and JK are corresponding parts, and sides FH and IK are corresponding parts.

CPCTC is an acronym for corresponding parts of congruent triangles are congruent.

Then, FG ≅ IJ, GH ≅ JK and FH ≅ IK

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A circle has a circumference of 150 meters. What is the measure of its radius? Round
Savatey [412]

Answer:

23.9 is the radius

Step-by-step explanation:

150/3.14 =47.7707006369

47.7707006369/2 = 23.8853503185

Round to nearest tenth = 23.9

Hope this helps!

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In the figure, m< DBE = 50. Find m< BED
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Could you please put the picture? what type of angle are we talking bout or figure please and thank you!
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Announcements for 84 upcoming engineering conferences were randomly picked from a stack of IEEE Spectrum magazines. The mean len
Marina86 [1]

Answer:

Step-by-step explanation:

Hello!

You need to construct a 95% CI for the population mean of the length of engineering conferences.

The variable has a normal distribution.

The information given is:

n= 84

x[bar]= 3.94

δ= 1.28

The formula for the Confidence interval is:

x[bar]±Z_{1-\alpha/2}*(δ/n)

Lower bound(Lb): 3.698

Upper bound(Ub): 4.182

Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242

I hope it helps!

6 0
2 years ago
Suppose f and g are continuous functions such that g(2) = 6 and lim x → 2 [3f(x) + f(x)g(x)] = 36. find f(2).
True [87]

Answer: f(2) = 4

Step-by-step explanation:

F(x) and g(x) are said to be continuous functions

Lim x=2 [3f(x) + f(x)g(x)] = 36

g(x) = 2

Limit x=2

[3f(2) + f(2)g(2)] = 36

[3f(2) + f(2) . 6] = 36

[3f(2) + 6f(2)] = 36

9f(2) = 36

Divide both sides by 9

f(2) = 36/9

f(2) = 4

7 0
2 years ago
12x+7<−11 AND5x−8≥4012
Arte-miy333 [17]

Answer:

No solution

Step-by-step explanation:

Given: 12x+7 and  5x-8\geq 40

Solve both inequality separately.

12x+7              Subtraction property of inequality

12x

12x

x

x

and

5x-8\geq 40               Addition property of inequality

5x\geq 40+8

5x\geq 48

x\geq \dfrac{48}{5}

Hence, the solution of the compound inequality intersection of both solutions.

Please find attachment for number line solution.

No solution

8 0
2 years ago
Read 2 more answers
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