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2 years ago

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Chester used the regression equation of the weight loss plan to make a prediction within the given data range. Complete his work

to calculate the number of weekly hours of aerobic activity needed for a monthly weight loss of 3 pounds. Round to the nearest hundredth.
1. Regression equation: y = 1.178 x + 0.71. 2. Substitute 3 for y: 3 = 1.178 x + 0.71. 3. Subtract 0.71 from both sides: 2.29 = 1.178 x. 4. Divided both sides by 1.178: StartFraction 2.29 Over 1.178 EndFraction = StartFraction 1.178 Over 1.178 EndFraction x.

About

hours of weekly aerobic activity will result in 3 pounds of monthly weight loss.

2 answers:

likoan [24]2 years ago

5 0

Answer: 1.94

Step-by-step explanation:

algol132 years ago

4 0

Answer: 1.94

Step-by-step explanation: I got it correct

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A poll stated that 32% of those polled think the economy is getting worse. An economist wanted to check this claim so she survey

zysi [14]

Answer:

$z=\frac{0.30 -0.32}{\sqrt{\frac{0.32(1-0.32)}{750}}}=-1.174$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level given we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.32 or 32 %

Step-by-step explanation:

Information given

n=750 represent the random sample taken

$\hat p=0.30$ estimated proportion of people who thought the economy is getting worse

$p_o=0.32$ is the value that we want to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to check if the true proportion of interest is equal to 0.32 or not.:

Null hypothesis: $p=0.32$

Alternative hypothesis: $p \neq 0.32$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.30 -0.32}{\sqrt{\frac{0.32(1-0.32)}{750}}}=-1.174$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level given we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.32 or 32 %

8 0

2 years ago

Clyde is baking, and the recipe requires 1 1/3 cups of flour. Clyde has 2 cups of flour, but he is doubling the recipe to make t

ki77a [65]

2 times 4/3= 8/3 8/3-6/3=2/3 therefore Clyde needs 2/3 cup more flour.

5 0

2 years ago

The length of the day in Boulder (Latitude 40 N) can be modeled approximately by l(t) = −3 cos ( 2π 365 (t + 10)) + 12 where l i

Harman [31]

Answer:

(a) I(355)=9

(b) I'(265)=−0.05163

(c) The l′(t) is largest at 81.25.

Step-by-step explanation:

The given function is

$I(t)=-3\cos (\frac{2\pi}{365}(t+10))+12$

where I(t) the length of the day in Boulder and l is given in hours and t is the day of the year.

(a)

Substitute t=355 in given function.

$I(355)=-3\cos (\frac{2\pi}{365}(355+10))+12$

$I(355)=-3\cos (2\pi)+12$

$I(355)=-3(1)+12$

$I(355)=9$

Therefore, the value of I(355) is 9. It means the length of the day in Boulder is 9 hours at 355 day of the year.

(b)

Differentiate the given function with respect to t.

$I'(t)=-3(-\sin (\frac{2\pi}{365}(t+10)))(\frac{2\pi}{365})$

$I'(t)=\frac{6\pi}{365}\sin (\frac{2\pi}{365}(t+10))$

Substitute t=265 in the above function.

$I'(t)=\frac{6\pi}{365}\sin (\frac{2\pi}{365}(265+10))$

$I'(265)\approx −0.05163$

Therefore, the value of I'(265) is −0.05163. It means the length of the day in Boulder decreased by 0.05163 hours at 265 day of the year.

(c)

Differentiate the I'(t) function with respect to t.

$I''(t)=\frac{6\pi}{365}\cos (\frac{2\pi}{365}(t+10))(\frac{2\pi}{365})$

$I''(t)=\frac{12\pi^2}{(365)^2}\cos (\frac{2\pi}{365}(t+10))$

Equate $I''(t)=0$ to find critical points.

$\frac{12\pi^2}{(365)^2}\cos (\frac{2\pi}{365}(t+10))=0$

$\cos (\frac{2\pi}{365}(t+10))=0$

$\cos (\frac{2\pi}{365}(t+10))=\cos (\frac{\pi}{2})$

On comparing both sides we get

$\frac{2\pi}{365}(t+10)=\frac{\pi}{2}$

$t+10=\frac{\pi}{2}\times \frac{365}{2\pi}$

$t+10=\frac{365}{4}$

$t=\frac{365}{4}-10$

$t=81.25$

Check the value of the function I'''(t) at t=81.25.

Since $I'''(81.25)=-0.0000153$ , therefore the value of l′(t) is largest at 81.25.

4 0

2 years ago

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below

Kay [80]

Answer:

Due to the higher z-score, Cade should be offered the job.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If the company has only one position to fill and prefers to fill it with the applicant who performed best on the aptitude test, which of the applicants should be offered the job?

Whoever had the higher z-score.

Reyna:

Reyna got a score of 75.3; this version has a mean of 69.3 and a standard deviation of 12.

This means that $X = 75.3, \mu = 69.3, \sigma = 12$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{75.3 - 69.3}{12}$

$Z = 0.5$

Kaitlyn:

Kaitlyn got a score of 228.4; this version has a mean of 206 and a standard deviation of 28.

This means that $X = 228.4, \mu = 206, \sigma = 28$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{228.4 - 206}{28}$

$Z = 0.8$

Cade:

Cade got a score of 7.88; this version has a mean of 7.2 and a standard deviation of 0.4. This means that $X = 7.88, \mu = 7.2, \sigma = 0.4$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{7.88 - 7.2}{0.4}$

$Z = 1.7$

Due to the higher z-score, Cade should be offered the job.

7 0

2 years ago

Maria has a set of 10 index cards labeled with the digits 0 through 9. She puts them in a bag and selects one at random. The out

Tom [10]

Answer:A

Step-by-step explanation: there are most odd number's through 0,9

6 0

2 years ago