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kirill115 [55]
2 years ago
14

The following dot plots shows the number of players injured per game for three different teams. Each dot represents a different

game. Order the teams from least to greatest typical number of injuries per game. Put the graph with the least typical value on top.
Mathematics
2 answers:
DanielleElmas [232]2 years ago
8 0

Answer:

Least to Greatest: Bulldogs, Cranidals, then Tornado.

Step-by-step explanation:

Trust me

goldenfox [79]2 years ago
7 0

Answer:

you have to put them in order dummy

Step-by-step explanation:

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A man bought 420 apples for Rs. 280 but 84 were rotten. Yet he earned 20%. Estimate how did he sell ?
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420-84=336(total apples sold)

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280+56=336Rs.(total sale)

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A truck delivers 478 dozen eggs to stores in one day. Write an expression that finds the number of eggs the truck delivers in on
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Read 2 more answers
Chin made an error in his chart showing the multiplication of the binomial by the trinomial. Which change can be made to correct
Tcecarenko [31]

Answer:

The expression 6x should be 6x²

Step-by-step-explanation:

The chart being referred to showing the multiplication of the binomial by the trinomial is given in the attached picture below.

To find out where Chin made an error in his multiplication, and also determine the right expression, let's take a look at each multiplication done. Thus we have:

3x*x² = 3x³

3x*2x = 6x² (here is where the error was made, in the chart, Chin wrote 6x)

3x*4 = 12x

2*x²=2x²

2*2x = 4x

2*4 = 8

Therefore, the expression 6x should be 6x²

7 0
2 years ago
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Exercise 5.6.6: Selecting a committee of senators. About A country has two political parties, the Demonstrators and the Repudiat
krok68 [10]

Answer:

There are 4,148,350,734,528 ways

Step-by-step explanation:

We have

  • 44 senators which are Demonstrators.
  • 56 senators which are Repudiators.

(a) How many ways are there to select a committee of 10 senate members with the same number of Demonstrators and Repudiators?

We want to choose 5 Demonstrators and 5 Repudiators. The number of ways to do this is {44} \choose {5} and 56 \choose 5 respectively. Therefore, the number of ways to select the committee is given by:

{{44}\choose {5}} \times {{56}\choose{5}}=\frac{44!}{39!5!}\times\frac{56!}{51!5!}=\frac{44!56!}{51!39!5!5!}=\frac{44\times43\times42\times41\times40\times56\times55\times54\times53\times52}{5!5!}=\\\\=\frac{44\times43\times42\times41\times8\times56\times11\times54\times53\times52}{4!4!}= \frac{11\times43\times42\times41\times2\times56\times11\times54\times53\times52}{3!3!}=\\\\\frac{11\times43\times14\times41\times2\times56\times11\times18\times53\times52}{2!2!}=

11\times43\times14\times41\times28\times11\times18\times53\times52=4,148,350,734,528

(b) Suppose that each party must select a speaker and a vice speaker. How many ways are there for the two speakers and two vice speakers to be selected?

  • <u>If the speaker and vice speaker are chosen between all senators:</u> In this case, the answer will be

44\times43\times56\times55=5,827,360.

This is because there are (in the case of Demonstrators) 44 possibilities to choose an speaker and after choosing one, there would be 43 possibilities to choose a vice speaker. The same situation happens in the case of Repudiators.

  • <u>If the speaker and vice speaker are chosen between the committee:</u> In this case, the answer will be

5\times4\times5\times4=400.

3 0
2 years ago
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