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2 years ago

San Jose's elevation is 87 feet. Salton City's elevation is -125 feet. Jackie claims that Salton

Mathematics

1 answer:

joja [24]2 years ago

7 0

Answer:

Third option

Step-by-step explanation:

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Tim Tradesman estimates his taxable income will be $7,500. He is paid every two weeks or 26 times a year.

alisha [4.7K]

Given:
Taxable income: 7,500
Paid every two weeks or 26 weeks in a year

Based on 2007 Federal Income Tax Table for Single Taxpayer, Tim is under the tax range over $0 but not over $7,825. The tax is 10% of the amount over $0.

<span>1. Finds the tax rate for his income level =10 %

2. Enters the base amount = $7,500

3. Enters the amount of tax owed = $7,500 * 10% = $750

4. Divides by 26 = $750 / 26 = $28.85 tax withheld from biweekly wages.</span>

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2 years ago

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1.488 divided by 2.1 rounded to nearest tenth

Neko [114]

The answer should be 0.70

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2 years ago

shanti wrote the predicted values for a data set using the line of best fit y = 2.55x – 3.15. she computed two of the residual v

Delvig [45]

<span>The question asks us to determine the values for a and b in the linear equation. Linear equation in the slope-intercept form is : y = a x + b. This equation is: y = 2.25 x - 3.15. The slope: a = 2.25 and the y-intercept is: b = -3.15. Answer: a = 2.25 and b = - 3.15.</span>

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2 years ago

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The positive difference between the two roots of the quadratic equation $3x^2 - 7x - 8 = 0$ can be written as $\frac{\sqrt{m}}{n

Sergio [31]

3x² - 7x - 8 = 0

We're asked about square roots so we won't try to factor; we'll go right for the quadratic formula,

x = ( 7 ± √(7² - 4(3)(-8)) )/(2(3)) = (7 ± √(49+96))/6 = 7/6 ± √145/6

145 = 5×29, so no square factors. The positive difference is

d = (7/6 + √145/6) - (7/6 - √145/6) = 2√145/6 = √145/3

so m=145, n=3 for a sum of

Answer: 148

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2 years ago

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A company manufacturing oil seals wants to establish X and R control charts on the process. There are 25 preliminary samples of

alisha [4.7K]

Answer:

A ) i) X control chart : upper limit = 50.475, lower limit = 49.825

ii) R control chart : upper limit = 1.191, lower limit = 0

Step-by-step explanation:

A) Finding the control limits

grand sample mean = 1253.75 / 25 = 50.15

mean range = 14.08 / 25 = 0.5632

Based on X control CHART

The upper control limit ( UCL ) =

grand sample mean + A2* mean range ) = 50.15 + 0.577(0.5632) = 50.475

The lower control limit (LCL)=

grand sample mean - A2 * mean range = 50.15 - 0.577(0.5632) = 49.825

Based on R control charts

The upper limit = D4 * mean range = 2.114 * 0.5632 = 1.191

The lower control limit = D3 * mean range = 0 * 0.5632 = 0

B) estimate the process mean and standard deviation

estimated process mean = 50.15 = grand sample mean

standard deviation = mean range / d2 = 0.5632 / 2.326 = 0.2421

note d2 is obtained from control table

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2 years ago