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2 years ago

Given 4 integers, output their product and their average, using integer arithmetic.

Computers and Technology

1 answer:

solmaris [256]2 years ago

8 0

Answer:

see explaination

Explanation:

Part 1:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

int avg=0, pro=1;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

avg = (num1+num2+num3+num4)/4;

pro = num1*num2*num3*num4;

System.out.println(pro+" "+avg);

}

------------------------------------------------------------------

Part 2:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

double avg=0, pro=1; //using double to store floating point numbers.

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

avg = (num1+num2+num3+num4)/4.0; //if avg is declared as a float, then use 4.0f

pro = num1*num2*num3*num4;

System.out.println((int)pro+" "+(int)avg); //using type conversion only integer part

System.out.printf("%.3f %.3f\n",pro,avg);// \n is for newline

}

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Answer:

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2 years ago

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Alekssandra [29.7K]

Answer:

Explanation:

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2 years ago

Given positive integer n, write a for loop that outputs the even numbers from n down to 0. If n is odd, start with the next lowe

seropon [69]

Answer:

The program in Python is as follows:

n = int(input("Enter an integer: "))

if n < 0:

n = 0

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Explanation:

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This iterates from n to 0

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1 year ago

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shusha [124]

Statement two and three is correct.

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2 years ago

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mario62 [17]

Solution :

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#constructor.

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$\text{self.nam}e$ = name

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return employee_dict

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