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2 years ago

Recunoasteti triunghiurile isoscele din figurile de mai jos:

Mathematics

1 answer:

yarga [219]2 years ago

8 0

Answer:

<h2>The right side triangle is isosceles and equilateral.</h2>

Step-by-step explanation:

In this problem we need to draw isosceles triangles with $AB=AC$ . The triangle is attached.

Also, we have to identify which triangle is isosceles based on the image. The triangle on the left is isosceles and equilateral. Remember that a isosceles triangle is defined by the congruence between at least two sides, in this case, we have three congruent sides, which makes the triangle isosceles and equilateral.

The triangle on the right side is not isosceles, it's just a right triangle. When a right triangle is also isosceles, its acute angles are 45°, which is not the case here.

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How many words can be formed by using the W,X,Y,Z if repetitions is not allowed?

Setler [38]

Answer:

Step-by-step explanation:

What you have here is a permutation, seeing as each element can only be used once.

We have 4 letters initially, so we can choose any 1 as our first letter. We have 4 choices for our first letter

However, once we choose our first letter, we can't use it anymore, so, for our second letter, we can only choose from the remaining 3 letters.

Furthermore, once we choose our second letter, we can only choose our 3rd letter from the remaining two letters we didn't choose yet.

Finally, our last letter will always be the one we didn't choose the last 3 times. So there is only one choice here.

Going off of this, we have four choices for the 1st letter, three choices for the 2nd letter, two choices for the 3rd letter, and one choice for the 4th letter

The way to calculate how many permutations we have without repetition is using factorials

Where N is the number of elements you have.

In this case, it would be 4!

4! is 4 * 3 * 2 * 1

Which equals 24

If you notice, each number in 4! is the number of options we have for each choice. 4, then 3, and so on

5 0

2 years ago

Steph makes 90\%90%90, percent of the free throws she attempts. She is going to shoot 333 free throws. Assume that the results o

nikitadnepr [17]

Answer:

0.03

Step-by-step explanation:

khan:)

7 0

2 years ago

Read 2 more answers

Factor 147a^2b-675b^3

Tju [1.3M]

Answer:Factor the polynomial

3(a−4b)2

8 0

2 years ago

A scientist studying water quality measures the lead level in parts per billion (ppb) at each of 49 randomly chosen locations al

NeX [460]

Complete Question

The complete qustion is shown on the first uploaded image

Answer:

The correct option is B

Step-by-step explanation:

From the question we are told that

The sample size is $n = 49$

The mean is $\mu = 17ppb$

The standard deviation is $\sigma = 14 ppb$

Generally the standard error of this measurement is mathematically represented as

$\sigma_z = \frac{\sigma}{\sqrt{n} }$

substituting values

$\sigma_{\= x} = \frac{14}{\sqrt{49} }$

$\sigma_{\= x} = 2$ ppb

Now the probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb represented as P(X < 15 )

Next is to find the z value

$z = \frac{\mu -\sigma }{\sigma_{\= x}}$

$z = \frac{15-17}{2}$

$z = -1$

Now checking the z-table for the z-score of -1 we have

$P(X$

5 0

2 years ago

6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the

MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

$a_1$ the horizontal distance between the first observer and the ballonist

$a_2$ the horizontal distance between the second observer and the ballonist

$\alpha _1$ and $\alpha _2$ the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

$S=a*h$ (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

$S=S_1+S_2$ (equation 2)

$S_1=a_1*h$

But we can write $S_1$ in terms of $\alpha _1$ , like this:

$\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}$

And for $S_2$ will be the same:

$S_2=\frac{h^{2} }{\tan(\alpha _2)}$

Replacing in the equation 2:

$S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})$

And replacing in the equation 1:

$h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}$

So, we can replace all the known data in the last equation:

$h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft$

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0

2 years ago