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Harrizon [31]
2 years ago
14

Given that OA= 11x +6y, OB=4x +10y and CO= - 13x+11y, write down each of the following vectors in its simplest form.

Mathematics
1 answer:
levacccp [35]2 years ago
8 0

Answer:

  • BA = 7x -4y
  • AC = 2x -17y

Step-by-step explanation:

a) BA = OA -OB = (11x+6y) -(4x +10y)

  BA = 7x -4y

__

b) AC = -CO -OA = -(-13x +11y) -(11x +6y)

  AC = 2x -17y

_____

The vector OC is the opposite of the vector CO.

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Zach read a book for 10 minutes every weekend in the first month, 20 minutes in the second month, 40 minutes in the third month,
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Zach time of reading every weekend forms a sequence with these terms: 10, 20, 40, 80. On the other hand, that of Victoria forms a sequence with terms: 35, 50, 65, 80. By keenly observing the sequences, Zach's sequence is a geometric sequence with a common ratio equal to 2 and Victoria's sequence is an arithmetic or linear sequence with a common difference of 15. Thus, the answer is letter B.
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Parallelogram ABCD is rotated to create image A'B'C'D'. On a coordinate plane, 2 parallelograms are shown. The first parallelogr
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Answer:

(x,y)→(y,-x)

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Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of
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<h2><u>Answer with explanation</u>:</h2>

As per given , we have

sample size : n= 65

degree of freedom : df=n-1=64

sample mean : \overline{x}=19.5

sample standard deviation : s= 5.2

Since , the population standard deviation is not given  , so we apply t-test.

Significance level  for 90% confidence : \alpha=1-0.90=0.10

t-critical value for significance level 0.10 and df = 64 would be :

t_c=t_{\alpha/2, df}=t_{0.05,\ 64}=1.6690

Formula for Confidence interval :

\overline{x}\pm t_c\dfrac{s}{\sqrt{n}}

Then , 90%  confidence intervals for the population mean number of weekly customer contacts for the sales personnel would be :

19.5\pm(1.669)\dfrac{5.2}{\sqrt{65}}

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Significance level  for 95% confidence : \alpha=1-0.95=0.05

t-critical value for significance level 0.05 and df = 64 would be :

t_c=t_{\alpha/2, df}=t_{0.05,\ 64}=1.9977

Then , 95%  confidence intervals for the population mean number of weekly customer contacts for the sales personnel would be :

19.5\pm(1.9977)\dfrac{5.2}{\sqrt{65}}

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(19.5-1.288,\ 19.5+1.288)=(18.212,\ 20.788)

∴ 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel : (18.212, 20.788)

4 0
2 years ago
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