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Harrizon [31]
2 years ago
14

Given that OA= 11x +6y, OB=4x +10y and CO= - 13x+11y, write down each of the following vectors in its simplest form.

Mathematics
1 answer:
levacccp [35]2 years ago
8 0

Answer:

  • BA = 7x -4y
  • AC = 2x -17y

Step-by-step explanation:

a) BA = OA -OB = (11x+6y) -(4x +10y)

  BA = 7x -4y

__

b) AC = -CO -OA = -(-13x +11y) -(11x +6y)

  AC = 2x -17y

_____

The vector OC is the opposite of the vector CO.

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Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22
GuDViN [60]

Answer:

b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8

Step-by-step explanation:

Consider the given matrix

A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]

Let matrix B is

B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

It is given that

A=B

\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

On comparing corresponding elements of both matrices, we get

b_{11}=9,b_{12}=-2,b_{13}=3

b_{21}=2,b_{22}=17,b_{23}=0

b_{31}=3,b_{32}=22,b_{33}=8

Therefore, the required values are b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8.

3 0
2 years ago
Read 2 more answers
Ava bought some pens for $ 2 each and some pencils for $ 1 each. She bought 3 more pens than pencils and spent a total of $ 12.
Rudiy27

Answer:

Step-by-step explanation:

price of 1 pen= $ 2

price of 1 pencil= $1

total money spent= $12

Let the number of pen be a and number of pencil be b.

 2 a + b = 12   ----------------Equation 1

We have, she bought 3 more pens than pencils

  a - b = 3   ------------------  Equation 2

 Equation 1 +Equation 2,  

   2 a + b +  a - b = 12 + 3

                     3a = 15

                     a = 5

 Substituting in  equation

           5 - b = 3

               b = 2

 Number pencils Ava bought = 2

5 0
2 years ago
A) Find the coordinates of the points of intersection of the graphs with coordinate axes: b y=−2x+4
vova2212 [387]

Answer:

Step-by-step explanation:

A)

y=−2x+4

y-int:

y=−2*0+4

y=4

x-int:

0=−2x+4

2x=4

x=2

(2,4)

B)

2x+3y=6

y-int:

2*0+3y=6

3y=6

y=2

x-int:

2x+3*0=6

2x=6

x=3

(3,2)

C)

1.2x+2.4y=4.8

y-int:

1.2*0+2.4y=4.8

2.4y=4.8

24y=48

y=2

x-int:

1.2x+2.4*0=4.8

1.2x=4.8

12x=48

x=4

(4,2)

4 0
2 years ago
The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci
Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that n = 300 and \pi = \frac{10}{300} = 0.033

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532

The correct answer is

(0.0128, 0.0532)

4 0
1 year ago
Expand the following expression by using the distributive method. 6(3b - 4c)
Kruka [31]
18b - 24c because you multiply the outside with everything inside

8 0
2 years ago
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