C
.) The - 3 at the end of the function means the function is shifted down 3 units. This also shifts the asymptote down 3 units.
There is a missing graph in the problem given. However, we can simply solve the equation using the given data.
Items to be sold: scarves and hats. Minimum of 20 items sold in all.
Scarves sell for 10 each and hats sell for 20 each. Must sell at least 300 worth of merchandise to make profit.
Let s represent scarves and h represent hats.
10s + 20h <u>></u> 300
s + h <u>></u> 20
We use inequality because the problem states "at least".
s + h = 20
10s + 20h = 300
s = 20 - h
10(20-h) + 20h = 300
200 - 10h + 20h = 300
10h = 300 - 200
10h = 100
h = 100/10
h = 10
s = 20 - h
s = 20 - 10
s = 10
s + h <u>></u> 20
10 + 10 <u>></u> 20
10s + 20h <u>></u> 300
10(10) + 20(10) <u>></u> 300
100 + 200 <u>></u> 300
<span>So
let’s simplify the given situation.
We need to find out how much heavier is 91/8 lbs. compare to 2 5/6 lbs.
Since, it’s a combination of whole number and fraction; we cannot directly
subtract this given equation. We need to convert the two given number into a
fraction.
9 1/8 = 8 x 9 = 72 + 1 = 73, 73 is our numerator and 8 is our denominator
=> 73/8
2 5/6 = 6 x 2 = 12 + 5 = 17, 17 is our numerator and 6 is our denominator
=> 17/6
Now, we have 2 fractions with unlike denominator. In order to get a common
denominator, we have to find their least common factor.
=> <u>73</u> - <u>17 </u> = <u>73 x 6 </u> - <u>17 x 8 </u> <u>
</u> 8 6
8 x 6 6
x 8</span><span>
=> <u>438</u> – <u>136 </u> Now, we
have the same denominator, subtract</span><span>
48 48
=> <u>302 </u> or <u>151</u>
48 24
=> 6 <u>7</u>
24
Therefore 9 1/8 lbs. is 6 7/24 lbs. heavier than 2 5/6 lbs.</span>
Answer: 1 / 27
Step-by-step explanation: p (B1) = 1 / 3
p (B2) = 1 / 3
p (B3) = 1 / 3
pro (B1 X B2 X B3) = 1 / 3 X 1 / 3 X 1 / 3 = 1 / 27
We are given
v = 18 m/hr west
θ1 = 285°
θ2 = 340°
After 1 hours, the distance traveled by the ship is
dv = 18 mi
The distance between the ship and the lighthouse is
d = 18 / cos 340
Solve for d<span />