Answer:

Step-by-step explanation:
Consider the given matrix
![A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D)
Let matrix B is
![B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
It is given that

![\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
On comparing corresponding elements of both matrices, we get



Therefore, the required values are  .
.
 
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
price of 1 pen= $ 2
price of 1 pencil= $1
total money spent= $12
Let the number of pen be a and number of pencil be b.
  2 a + b = 12   ----------------Equation 1
 We have, she bought 3 more pens than pencils
   a - b = 3   ------------------  Equation 2
  Equation 1 +Equation 2,  
    2 a + b +  a - b = 12 + 3
                      3a = 15
                      a = 5
  Substituting in  equation
            5 - b = 3
                b = 2
  Number pencils Ava bought = 2
 
        
             
        
        
        
Answer:
Step-by-step explanation:
A)
y=−2x+4
y-int:
y=−2*0+4
y=4
x-int:
0=−2x+4
2x=4
x=2
(2,4)
B)
2x+3y=6
y-int:
2*0+3y=6
3y=6
y=2
x-int:
2x+3*0=6
2x=6
x=3
(3,2)
C)
1.2x+2.4y=4.8
y-int:
1.2*0+2.4y=4.8
2.4y=4.8
24y=48
y=2
x-int:
1.2x+2.4*0=4.8
1.2x=4.8
12x=48
x=4
(4,2)
 
        
             
        
        
        
Answer:
The correct answer is
(0.0128, 0.0532)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of  , and a confidence interval
, and a confidence interval  , we have the following confidence interval of proportions.
, we have the following confidence interval of proportions.

In which
Z is the zscore that has a pvalue of 
For this problem, we have that:
In a random sample of 300 circuits, 10 are defective. This means that  and
 and 
Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.
So  = 0.05, z is the value of Z that has a pvalue of
 = 0.05, z is the value of Z that has a pvalue of  , so
, so  .
.
The lower limit of this interval is:

The upper limit of this interval is:

The correct answer is
(0.0128, 0.0532)
 
        
             
        
        
        
18b - 24c because you multiply the outside with everything inside