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egoroff_w [7]
2 years ago
10

The molar mass of sucrose (C12H22O11) is 342.3 g/mol. A chemist has a 0.500-mol sample of sucrose. What is the mass, in grams, o

f this sample?
a) 171

b) 342

c)500

d)684
Chemistry
1 answer:
Kryger [21]2 years ago
6 0

Answer:

a) 171

Explanation:

We can find the mass (in grams) of a sample by multiplying the amount of moles by the molar mass.

In this case, we know we have 0.500-mol and would multiply it by the molar mass, 342.3g/mol, to give us the answer of 171.15g rounded down to 171g.

Equation: 0.500mol x 342.3g/mol = 171.15g

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The 1996 NHTSA study, Crash Outcome Data Evaluation System (CODES), related traffic flow and medicinal accounts in seven states to measure entire costs of wound from motor vehicle crashes. The research originate that the mean inpatient costs for crash fatalities who were not using safety belts were 55 percent <span>higher than for those who were belted.</span>
5 0
2 years ago
Consider the dissolution of 1.50 grams of salt XY in 75.0 mL of water within a calorimeter. The temperature of the water decreas
-BARSIC- [3]

Answer:

The quantity of heat lost by the surroundings is 258,5J

Explanation:

The dissolution of salt XY is endothermic because the water temperature decreased.

The total heat consumed by the dissolution process is:

4,184 J/g°C × (75,0 + 1,50 g) × 0,93°C = 297,7 J

This heat is consumed by the calorimeter and by the surroundings.

The heat consumed by the calorimeter is:

42,2 J/°C × (0,93°C) = 39,2 J

That means that the quantity of heat lost by the surroundings is:

297,7J - 39,2J = <em>258,5 J</em>

I hope it helps!

8 0
2 years ago
Paintball is a popular recreational activity that uses a metal tank of compressed carbon
Dovator [93]

Answer:

Explanation:

Here we have the mass of CO₂ added = 340 g

From

Number \, of \, moles = \frac{Mass}{Molar \, mass}

We have, where the molar mass of CO₂ is 44.01 g/mol

Therefore,

Number \, of \, moles = \frac{340}{44.01} = 7.73 \, \, \, moles

71. Included drawing attached

72. Here we have the pressure of the gas given by Charles law which can be resented as follows;

\frac{P_1}{P_2} =\frac{T_1}{T_2}

Where:

P₁ = Initial pressure = 6.1 atmospheres

P₂ = Final pressure

T₁ = Initial Temperature = 293 K

T₂ = Initial Temperature = 313 K

Therefore,

P_2= T_2 \times \frac{P_1}{T_1} = 313 \times \frac{6.1}{293} = 3.312 \, \, \, atmospheres

 

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2 years ago
A certain electrochemical cell has for its cell reaction: zn + hgo → zno + hg which is the half-reaction occurring at the anode?
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2 years ago
A chemist wants to extract copper metal from copper chloride solution. The chemist places 1.50 grams of aluminum foil in a solut
Lisa [10]

Answer: d. More than 6.5 grams of copper (II) is formed, and some copper chloride is left in the reaction mixture.

Explanation: 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

As can be seen from the chemical equation, 2 moles of aluminium react with 3 moles of copper chloride.

According to mole concept, 1 mole of every substance weighs equal to its molar mass.

Aluminium is the limiting reagent as it limits the formation of product and copper chloride is the excess reagent as (14-7.5)=6.5 g is left as such.

Thus 54 g of of aluminium react with 270 g of copper chloride.

1.50 g of aluminium react with=\frac{270}{54}\times 1.50=7.5 gof copper chloride.

3 moles of copper chloride gives 3 moles of copper.

7.5 g of copper chloride gives 7.5 g of copper.

8 0
2 years ago
Read 2 more answers
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