Question

Suppose two clowns on skateboards are standing motionless on a smooth surface 2.0 m apart. Clown B tosses a 5.0 kg medicine ball to Clown A. After the throw the medicine ball is traveling with a speed of 10 m/s. What is the resulting velocity of Clown B after throwing the ball? *Indicate which direction is positive.

Answer 1

Answer:

Explanation:

Suppose two clowns on skateboards are standing motionless on a smooth surface 2.0 m apart. Clown B tosses a 5.0 kg medicine ball to Clown A. After the throw the medicine ball is traveling with a speed of 10 m/s. What is the resulting velocity of Clown B after throwing the ball? *Indicate which direction is positive.

By momentum conservation

Momentum of ball $m_b$= 10 . 5 = 50 kg m/s

$m_1v_1=m_bv_b$

$70v_1= 5\times 10$

$v_1 = 0,714m/s$ left

$m_2v_2=m_bv_b$

$50\times10 = 50 v_b$

$v_2= 1m/s$ Right