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2 years ago

Which best describes what occurs when a body accelerates?

1 answer:

6 0

A body accelerates due to net force acting on it. As newton's second law of motion states:

when a net force acts on a body, it produces acceleration in the body in the direction of the net force

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What is the atomic number z of 73li?

aev [14]

I think thats a trick question on the periodic table there is no Z, theres Zi which is zinc but no Z

3 0

2 years ago

Read 2 more answers

The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles

belka [17]

Answer:

$F_a=5.67\times 10^{-5}\ N$

$F_b=3.49\times 10^{-5}\ N$

$F_c=9.16\times 10^{-5}\ N$

Explanation:

Given:

mass of particle A, $m_a=363\ kg$

mass of particle B, $m_b=517\ kg$

mass of particle C, $m_c=154\ kg$

All the three particles lie on a straight line.

Distance between particle A and B, $x_{ab}=0.5\ m$

Distance between particle B and C, $x_{bc}=0.25\ m$

Since the gravitational force is attractive in nature it will add up when enacted from the same direction.

Force on particle A due to particles B & C:

$F_a=G. \frac{m_a.m_b}{x_{ab}^2} +G. \frac{m_a.m_c}{(x_{ab}+x_{bc})^2}$

$F_a=6.67\times 10^{-11}\times (\frac{363\times 517}{0.5^2}+\frac{363\times 154}{(0.5+0.25)^2})$

$F_a=5.67\times 10^{-5}\ N$

Force on particle C due to particles B & A:

$F_c=G.\frac{m_c.m_b}{x_{bc}^2} +G.\frac{m_c.m_a}{(x_{ab}+x_{bc})^2}$

$F_c=6.67\times 10^{-11}\times (\frac{154\times 517}{0.25^2}+\frac{154\times 363}{(0.25+0.5)^2} )$

$F_c=9.16\times 10^{-5}\ N$

Force on particle B due to particles C & A:

$F_b=G.\frac{m_b.m_c}{x_{bc}^2} -G.\frac{m_b.m_a}{x_{ab}^2}$

$F_b=6.67\times 10^{-11}\times (\frac{517\times 154}{0.25^2}-\frac{517\times 363}{0.5^2} )$

$F_b=3.49\times 10^{-5}\ N$

3 0

2 years ago

A person driving a car applies the brakes. This produces friction, which stops the car. Into which type of energy is the mechani

Makovka662 [10]

D) Heat, because friction produces heat, not light, gravitational or chemical. hope this helps! : )

7 0

2 years ago

Read 2 more answers

There are two forces on the 2 kg box in the overhead view of the following figure, but only one is shown. For F1=20N, a= 12 m/s2

maw [93]

Answer:

second force = 32.784

Magnitude = $\sqrt{32.784$

θ = -90°

Explanation:

Fnet = ma

F1 + F2 = ma

20N + F2 = 2(12 × cos30° + 12 ×sin30°)

F2 = 2 × 12 ( sin 30° + cos 30°)

= 24 × ( 1 + √3 )÷ 2

=12 (1 +√3 )

= 32.784

b) $\sqrt{12(1 +\sqrt{3}}$

= $\sqrt{12 ( 1+ 1.732)}$

= $\sqrt{12 (2.732)}$

= $\sqrt{32.784}$

θ = 30° + 180°

θ = 210°

210° - 300°

θ = -90°

8 0

2 years ago

The force sensor measures the force on the sensor due to the bumper, but the cart's momentum change arises from the force on the

Irina-Kira [14]

Answer:

Answered

Explanation:

1 and 3 are necessary

Every bit of force applied to the bumper will be transmitted to the cart EXCEPT for the force needed to accelerate the bumper. This is the net force on the bumper.

If the bumper was heavy then a significant amount of force might be needed to accelerate the bumper so the amount transmitted to the cart would be substantially reduced.

If the net force on the bumper is small then the amount transmitted to the cart is almost the entire force applied.

5 0

2 years ago