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zhannawk [14.2K]
2 years ago
7

Petrich is wrapping four presents for his mom, dad, sister, and daughter. The following are the estimate box sizes:

Mathematics
1 answer:
Kruka [31]2 years ago
5 0

Answer:

Minimum 2 rolls will be required.

Step-by-step explanation:

Surface area of all three boxes = Area of the wrapping paper required

Surface area of Box 1 = 2(lb + bh + hl)

                                    = 2(8.5×14.5 + 14.5×1.5 + 8.5×1.5)

                                    = 315.5 square inches

Surface area of box 2 = 2(9.5×14.5 + 14.5×2 + 9.5×2)

                                    = 371.5 square inches

Surface area of box 3 = 2(15.5×12 + 12×4 + 15.5×4)

                                    = 592 square inches

Surface area of box 4 = 2(11×16 + 16×3 + 11×3)

                                    = 514 square inches

Total surface area = 315.5 + 371.5 + 592 + 514

                               = 1793 square inches

Dimensions of the wrapping paper = 30" × 9 feet Or 30" × 108"

Area of the wrapping paper = 3240 square inches

Number of papers required to wrap all four boxes =  \frac{3240}{1793}=1.8

                                                                                    ≈ 2 rolls  

Therefore, minimum 2 rolls will be required to wrap the presents.                          

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Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.

the formula for a combination is

C(n,r)= \frac{n!}{r!(n-r)!}

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C(11,4)= \frac{11!}{4!(11-4)!} 

She has 330 possible choices  to come home with 4 pieces of jewelry



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2 years ago
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kotegsom [21]

Answer:

28%

Step-by-step explanation:

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Then you must convert that into a percentage:

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Hope this helps you out! : )

4 0
2 years ago
Students voted on a school trip. 56 voted for the museum, 86 for the nature center, 172 for the state capital, and 116 for other
OLga [1]

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a = state capital

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Step-by-step explanation:

3 0
2 years ago
Find the exact value for cos π 12 applying sum and difference formulas involving π 3 and π 4 .
nadya68 [22]

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cos(π/3−π/4)

Use the difference formula for cosine to simplify the expression. The formula states that cos(A−B)=cos(A)cos(B)+sin(A)sin(B)

cos(π/3)⋅cos(π/4)+sin(π/3)⋅sin(π/4)

The exact value of cos(π/3) is 12, so:

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The exact value of sin(π/3) is √32.

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The exact value of sin(π/4) is √22.

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Simplify each term:

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Combine the numerators over the common denominator.

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8 0
2 years ago
The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
Anit [1.1K]

Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : 8d^5-3c^3d^2+5c^2d^3-4cd^4+9

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According to the question:

8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)

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Solving the like terms in above equation we get:

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Hence, the correct option is A.

5 0
2 years ago
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