Answer:
81.85% of the workers spend between 50 and 110 commuting to work
Step-by-step explanation:
We can assume that the distribution is Normal (or approximately Normal) because we know that it is symmetric and mound-shaped.
We call X the time spend from one worker; X has distribution N(μ = 70, σ = 20). In order to make computations, we take W, the standarization of X, whose distribution is N(0,1)
The values of the cummulative distribution function of the standard normal, which we denote 
, are tabulated. You can find those values in the attached file.
Using the symmetry of the Normal density function, we have that 
. Hece,
The probability for a worker to spend that time commuting is 0.8185. We conclude that 81.85% of the workers spend between 50 and 110 commuting to work.
I think the most likely representative sample had more girls than boys that were surveyed for it.
Answer:
(4* 1) + (9 * 1/10) + (2 * 1/1000)
Step-by-step explanation:
Given the figure : 4.902
Writw the figure above in expanded form:
4.902
Using the place value indicators :
Unit___tenth___hundredth___thousandth
4______9_______0___________2
Unit:
4 × 1
After the decimal point :
Tenth :
9 × 1/10 =
Hundredth :
0 * 1/ 100
Thousandth:
2 * 1/1000
Hence :
(4* 1) + (9 * 1/10) + 0 + (2 * 1/1000)
Answer:
The linear function that models the population of bloater fish is y2 =
✔ –92.57x + 1,052
.
The linear equation that determines when the two populations were equal is
✔ –19.76x + 227 = –92.57x + 1052
.
The solution is x =
✔ 11.33
years.
Step-by-step explanation:
