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OleMash [197]
2 years ago
7

Five light bulbs that are either on or off are lined up in a row. A certain code uses different combinations of lights turned on

to represent
different words. If exactly 2 lights must be turned on to represent a word, how many different words can be formed using the 5 light
bulbs? (1 point)
Mathematics
1 answer:
Paraphin [41]2 years ago
7 0

Answer:

10

Step-by-step explanation:

The number of different ways that 2 lights can be chosen from 5 is ₅C₂.  Use a calculator or find the value manually:

₅C₂ = 5! / (2! (5−2)!)

₅C₂ = 5! / (2! 3!)

₅C₂ = 5×4×3×2×1 / (2×1 × 3×2×1)

₅C₂ = 5×4 / 2

₅C₂ = 10

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Please help I will give brainliest
lutik1710 [3]

Answer:

Angle PQW is equal to 35 degrees

Step-by-step explanation:

Angle PQW = 36x - 1

Angle WQR = 134x

Angle PQR = 169 degrees

To find angle PQW, Set Angles PQR and WQR to PQW. The equation should look like this:

PQR - WQR = PQW

Substitute in the values

169 - 134x = 36x - 1

Now add 134x to both sides and add 1 to both sides.

170 = 170x

Now divide 170 from both sides

x = 1

Plug x into angle PQW

36(1) - 1 = 35

6 0
2 years ago
Beth wants to make exactly 60 blueberry muffins. Each batch makes 6 muffins, She has already made 2.5 batches. How many more bat
Katarina [22]

Answer: 4.5

You need that many more batches

8 0
2 years ago
Read 2 more answers
calculeaza lungimea segmentului ab in fiecare dintre cazuri:A(1,5);B(4,5);A(2,-5),B(2,7);A(3,1)B(-1,4);A(-2,-5)B(3,7);A(5,4);B(-
Tatiana [17]

Answer:

1. 3; 2. 12; 3. 5; 4. 13; 5. 10; 6. 10

Step-by-step explanation:

We can use the distance formula to calculate the lengths of the line segments.

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}

1. A (1,5), B (4,5) (red)

d = \sqrt{(x_{2} - x_{1}^{2}) + (y_{2} - y_{1})^{2}} = \sqrt{(4 - 1)^{2} + (5 - 5)^{2}}\\= \sqrt{3^{2} + 0^{2}} = \sqrt{9 + 0} = \sqrt{9} = \mathbf{3}

2. A (2,-5), B (2,7) (blue)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(2 - 2)^{2} + (7 - (-5))^{2}}\\= \sqrt{0^{2} + 12^{2}} = \sqrt{0 + 144} = \sqrt{144} = \mathbf{12}

3. A (3,1), B (-1,4 ) (green)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-1 - 3)^{2} + (4 - 1)^{2}}\\= \sqrt{(-4)^{2} + 3^{2}} = \sqrt{16 + 9} = \sqrt{25} = \mathbf{5}

4. A (-2,-5), B (3,7) (orange)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(3 - (-2))^{2} + (7 - (-5))^{2}}\\= \sqrt{5^{2} + 12^{2}} = \sqrt{25 + 144} = \sqrt{169} = \mathbf{13}

5. A (5,4), B (-3,-2) (purple)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-3 - 5)^{2} + (-2 - 4)^{2}}\\= \sqrt{(-8)^{2} + (-6)^{2}} = \sqrt{64 + 36} = \sqrt{100} = \mathbf{10}

6. A (1,-8), B (-5,0) (black)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-5 - 1)^{2} + (0 - (-8))^{2}}\\-= \sqrt{(-6)^{2} + (-8)^{2}} = \sqrt{36 + 64} = \sqrt{100} = \mathbf{10}

6 0
2 years ago
B(n)=−4−2(n−1)b, left parenthesis, n, right parenthesis, equals, minus, 4, minus, 2, left parenthesis, n, minus, 1, right parent
Inessa05 [86]

Answer:

12th term would be -26.

Step-by-step explanation:

Given explicit formula of a sequence,

b(n) = -4 - 2(n-1)

Where,

n = number of a term.

i.e. 12th term will get after putting n = 12 in the formula.

Hence, 12th term of the sequence would be,

b(12) = -4 - 2(12-1)

=-4-2(11)

= -4 - 22

= -26

8 0
2 years ago
The total cost of renting a car is $35.00 for each day the car is rented plus 37.5 cents for each mile the car is driven. what i
charle [14.2K]
X = days rented and y = miles driven
4 days rented and 300 miles driven

35x + .375y = total cost

35(4) + .375(300) 
140 + 112.5

Total cost = $252.50

6 0
2 years ago
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