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2 years ago

7

Five light bulbs that are either on or off are lined up in a row. A certain code uses different combinations of lights turned on

to represent
different words. If exactly 2 lights must be turned on to represent a word, how many different words can be formed using the 5 light
bulbs? (1 point)

1 answer:

Paraphin [41]2 years ago

7 0

Answer:

10

Step-by-step explanation:

The number of different ways that 2 lights can be chosen from 5 is ₅C₂. Use a calculator or find the value manually:

₅C₂ = 5! / (2! (5−2)!)

₅C₂ = 5! / (2! 3!)

₅C₂ = 5×4×3×2×1 / (2×1 × 3×2×1)

₅C₂ = 5×4 / 2

₅C₂ = 10

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If s is Julian’s savings, evaluate the expression when s = $125. First, write the expression . Second, 125 in for the variable s

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Answer:

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s/2

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Step-by-step explanation:

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2 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{2};$
$5\cdot 4=20=\overline{7};$
$5\cdot 5=25=\overline{12};$
$5\cdot 6=30=\overline{4};$
$5\cdot 7=35=\overline{9};$
$5\cdot 8=40=\overline{1};$
$5\cdot 9=45=\overline{6};$
$5\cdot 10=50=\overline{11};$
$5\cdot 11=55=\overline{3};$
$5\cdot 12=60=\overline{8}.$

The multiplicative inverse of 5 in $Z_{13}$ is 8.

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Mr. jovanovski is having wood flooring put in his rectangular living room. the area of the room is 234 square feet. the length o

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By definition the area of a rectangle is:
A = l * w
Where,
l: long
w: width
So we have to clear the width:
w = A / l
Substituting the values:
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w = 13 feets
answer
the width, in feet, of the room is 13

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Choose the algebraic expression that represents the area of a triangle that has a base 8 inches less than 2 times wider than the

loris [4]

Answer:

B. (1/2)(2h-8)(h)

Step-by-step explanation:

Area of a triangle = 1/2 × base × height

Let

Height = h

Base = 8 inches less than 2 times wider than the hight

= 2h-8

Substituting the values of base and height into the formula

We have,

Area of a triangle = 1/2 × base × height

= 1/2 × (2h-8) × h

= (1/2)(2h-8)(h)

The correct answer is option

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2 y + z = 457.50 (we will use the elimination method)
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3 y - z = 35
2 y + z = 457.50
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2 years ago

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