To answer the question, all the statements must be analyzed with the data presented in the table.
From the table we get that the team played 16 games at home and 11 games away from home.
In total, they played 27 games.
Of the 16 games at home, the team won 6. Then, the proportion of games won at home is:
6/16 = 0.375.
Of the 11 games away from home, the team won 3. Then the proportion of games won away from home is:
3/11 = 0.272.
0.375 is not twice 0.272.
Then the first statement is incorrect.
The ratio of games won at home is 6/16 = 3/8. Therefore, the second statement is incorrect. The team does not win 3/5 of the games at home.
The total number of games won is 9 and the total number of games is 27.
So, the third statement is incorrect. The team does not win half of the games.
The fourth statement is true. The team played 27 games
The fifth statement is false because the team won more than 6 games. They won 3 games away from home and 6 games at home
Finally, the sixth statement is correct, because the team lost 10 games at home and 8 away from home. However, the PERCENTAGE of games lost away from home is greater than the PERCENTAGE of games lost at home. Therefore, it is more likely that the team loses when playing away from home.
Let
X-----------------> number of pansies
y-----------------> number of trees
we know that
x=15*8----------> x=120 pansies
y=8 trees
cost of each trees is----------> $<span>20.75
</span>cost of each pansies is------> $2.50/6------> $5/12
[<span>expression to find Katherine’s final cost]=[cost trees]+[cost pansies]
</span>[cost trees]=y*$20.75
[cost pansies]=x*($5/12)
[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)
[expression to find Katherine’s final cost]=$166+$50
[expression to find Katherine’s final cost]=$216
the answer is
[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)
Katherine’s final cost is $216
To simplify the given radical form, we must recall some properties of exponents as shown below.
1. 1/x⁻ⁿ = xⁿ
2. x¹/² = √x
Now, going back to 1/x⁻³/⁶, we have
1/x⁻³/⁶ = x³/⁶
x³/⁶ = x¹/²
x¹/² = √x
Using the properties provided, we have a simplified form of √x.
<span>Answer: √x</span>
Answer:
Fernando incorrectly found the product of –2 and –5.
Step-by-step explanation:
Fernando evaluated the numerator of the fraction incorrectly.
Fernando simplified StartFraction 20 over 2 EndFraction incorrectly.
Fernando incorrectly found the product of –2 and –5.
Fernando evaluated (negative 3) squared incorrectly.
Fernando's calculation
5(9-5) / 2 + (-2)(-5) + (-3)^2
= 5(4) / 2 - 10 + 9
= 20/2 - 10 + 9
= 10 - 10 + 9
= 9
Correct calculation
5(9-5) / 2 + (-2)(-5) + (-3)^2
= 5(4) / 2 + (10) + 9
= 20/2 + 10 + 9
= 10 + 10 + 9
= 29
Therefore,
Fernando's error was multiplying (-2)(-5) to be equal to -10 instead of 10
Fernando incorrectly found the product of –2 and –5.
