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Nikolay [14]
2 years ago
4

1.4.2 Suppose a car dealership offers a low interest rate and a longer payoff period to customers or a high interest rate and a

shorter payoff period to customers, and most customers choose the low interest rate and longer payoff period, does that mean that most customers want a lower interest rate? Explain.
Mathematics
1 answer:
Marysya12 [62]2 years ago
7 0

Answer:

Yes, customers that deal on cars

But no, if not car customers.

Step-by-step explanation:

Most customers of cars want lower interest rate because it gives them opportunity to work for a longer period and gradually make the profit and pay back.

Even if it will take time that was why the dealer made it longer time.

But this might not apply to customer to other services because they might have their own principles or government/policies or interest rate to their customers.

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Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th
larisa86 [58]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

p_v =2*P(z>0.546)=0.585  

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

\hat p=0.2 estimated proportion  

p_o=0.16 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>0.546)=0.585  

4 0
2 years ago
2m - nx = x + 4 with description
3241004551 [841]
Since <span>x</span> contains the variable to solve for, move it to the left side of the equation by subtracting <span>x</span> from both sides.<span><span><span><span><span>2m</span><span><span>−n</span>x</span></span><span>−x</span></span>=4
</span></span>Since 2m does not contain the variable to solve for, move it to the right side of the equation by subtracting 2m from both sides.<span><span><span><span><span>n</span>x</span><span>-x</span></span>=<span><span><span>-2</span>m</span>+4</span></span></span>Factor <span>x</span> out of <span><span><span><span>−n</span>x</span><span>−x</span></span></span><span><span><span>x<span>(<span><span>−n</span><span>−1</span></span>)</span></span>=<span><span><span>−2</span>m</span>+4</span></span></span>Divide each term by <span><span><span>−n</span><span>−1</span></span><span><span>-n</span><span>-1</span></span></span> and simplify.<span>x=<span><span><span>2<span>(<span>m<span>−2</span></span>)/</span></span><span>n+1</span></span></span></span>
7 0
2 years ago
Cynthia rounds a number, x,to one decimal place. the result is 6.3.
gladu [14]

The answer is: 6.25\leq6.3

The explanation is shown below:

1. Cynthia rounds the number, which is identified as x, to one decimal place and the result is 6.3.

2. Based on this, we know that x could have been between 6.25 and 6.35. Therefore, the error interval for x is given by:

 6.25\leq6.3

Where \leq indicates that the value 6.25 is included and indicates that the value 6.35 is not included (Because if x had been exactly 6.35, Cynthia would round up to 6.4).

7 0
2 years ago
Find H.C.F. and L.C.M. of x3-y3, x2-y2 and (x-y) ?​
maks197457 [2]

Answer:

1) x³-y³ = (x-y)(x²-xy+y²)

2)x²-y² =(x-y)(x+y)

3)x-y = (x-y)

hcf = (x-y)

lcm = (x-y)(x²-xy+y²)(x+y)= (x³-y³)(x+y)

Step-by-step explanation:

5 0
2 years ago
Consider the system of equations. y = 3x + 2 y = − 2 3 x − 4 Explain why these particular equations can be graphed immediately.
Kay [80]
It’s because you already have the y-intercepts and the slope for both equations so graphing would be simple.

i hope this helps <3
5 0
2 years ago
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