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Juliette [100K]
2 years ago
14

Factorise 15x- 10x^3

Mathematics
2 answers:
BartSMP [9]2 years ago
8 0

Answer:

5x(3-2x^2)

Step-by-step explanation:

maksim [4K]2 years ago
4 0

Answer:

5x (3-2x^2)

Step-by-step explanation:

so all you have to do is 15x-10x=5x right?, then all you have to do is 15/5=3. 10x/5x=2x. then subtract 1 from the exponents. then you get the answer. okay Im sure about the fist part and the divison but not the exponents, I did use a calculator to check it though.

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The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act
stealth61 [152]

Answer:  0.2551

Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the actual temperature of the medium, and standard deviation σ.

Significance level : \alpha=1-0.95=0.05

The critical z-value for 95% confidence : z_{\alpha/2}=1.960 (1)

Since , z=\dfrac{x-\mu}{\sigma} (where x be any random variable that represents the temperature reading from a thermocouple.)

Then, from (1)

\dfrac{x-\mu}{\sigma}=1.96\\\\ x-\mu=1.96\sigma     (2)

Also,  all readings are within 0.5° of μ,

i.e. x-\mu

i.e. 1.96\sigma   [From (2)]

i.e. \sigma  

i.e. \sigma\approx0.2551

The required standard deviation : \sigma=0.2551

3 0
2 years ago
CL 6-131. Solve each system using the method of your choice.
shepuryov [24]

System 1: The solution is (x, y) = (-4, 5)

System 2:  The solution is (x, y) = (\frac{11}{3}, -3)

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

2x + 3y = 7 ------ eqn 1

-3x - 5y = -13 --------- eqn 2

We can solve by elimination method

Multiply eqn 1 by 3

6x + 9y = 21 ------ eqn 3

Multiply eqn 2 by 2

-6x - 10y = -26 ------- eqn 4

Add eqn 3 and eqn 4

6x + 9y -6x - 10y = 21 - 26

-y = -5

y = 5

Substitute y = 5 in eqn 1

2x + 3(5) = 7

2x + 15 = 7

2x = -8

x = -4

Thus the solution is (x, y) = (-4, 5)

<h3><em><u>Second system of equation is:</u></em></h3>

8 - y = 3x ------ eqn 1

2y + 3x = 5 ----- eqn 2

We can solve by susbtitution method

From given,

y = 8 - 3x ----- eqn 3

Substitute eqn 3 in eqn 2

2(8 - 3x) + 3x = 5

16 - 6x + 3x = 5

3x = 16 - 5

3x = 11

x = \frac{11}{3}

Substitute the above value of x in eqn 3

y = 8 - 3x

y = 8 - 3 \times \frac{11}{3}\\\\y = 8 - 11\\\\y = -3

Thus the solution is (x, y) = (\frac{11}{3}, -3)

4 0
2 years ago
Fran graphs the equations y = 2x2 – 2 and y = –0.5x + 4. Her graph is shown below. mc010-1.jpg Which value is an approximate sol
miv72 [106K]
On the added picture you can see that graphs of functions y=2x^2-2 and y=-0.5x+4 have two points of intersection. The x-coordinates of these points are the solutions of the equation 
2x^2-2=-0.5x+4.
Hence, the approximate solutions are x=-1.9 and x=1.6.


3 0
2 years ago
Read 2 more answers
An equation was created for the line of best fit from actual enrollment data. It was used to predict the dance studio enrollment
stealth61 [152]

Answer:  First option is correct.

Step-by-step explanation:

Enrollment month   Actual   Predicted   Residual

January                   500           8                4

February                 400           15              -1

March                     550            15              -1

April                         13              12              -1

May                         16              17              -1

June                        14              15              -1

Since we know that

Residual value = Actual value - Predicted value

Sum of residuals is given by

4-1-1+1-1-1=1

since we can see that sum of residual is more than 0.

So, it can't be a good fit .

Hence, No, the equation is not a good fit because the sum of the residuals is a large number.

Therefore, First option is correct.

6 0
2 years ago
A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a
stealth61 [152]

Answer:

a) 0.954

b) 0.937

c) 0.891  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  6 percent

Standard Deviation, σ = 1.3 percent

We are given that the distribution of particular interest rate is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(At least 3.8 percent.)

P(x \geq 3.8)

P( x \geq 3.8) = P( z \geq \displaystyle\frac{3.8 - 6}{1.3}) = P(z > -1.69)

= 1 - P(z < -1.69)

Calculation the value from standard normal z table, we have,  

P(x \geq 3.8) = 1 - 0.046 = 0.954 = 95.4\%

b) P(At most 8 percent)

P(x \leq 8) = P(z \leq \displaystyle\frac{8-6}{1.3}) = P(z \leq 1.53)

Calculating the value from the standard normal table we have,

P( x \leq 8) =0.937= 93.7\%

c) P(Between 3.8 percent and 8 percent. )

P(3.8 \leq x \leq 8) = P(-1.69 \leq z \leq 1.53)\\\\= P(z \leq 1.53) - P(z < -1.69)\\= 0.937 - 0.046 = 0.891 = 89.1\%

P(3.8 \leq x \leq 8) = 89.1\%

3 0
2 years ago
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