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Goshia [24]
2 years ago
11

The hourly wages earned by 20 employees are shown in the first box-and-whisker plot below. The person earning $15 per hour quits

and is replaced with a person earning $8 per hour. The graph of the resulting salaries is shown in plot 2. A box-and-whisker plot is shown. The number line goes from 7 to 15. The whiskers range from 8 to 15, and the box ranges from 8.8 to 10.2. A line divides the box at 9.5. Plot 1 A box-and-whisker plot is shown. The number line goes from 7 to 15. The whiskers range from 8 to 11, and the box ranges from 8.7 to 10. A line divides the box at 9.6. Plot 2 How does the mean and median change from plot 1 to plot 2? The mean and median remain the same. The mean decreases, and the median remains the same. The mean remains the same, and the median decreases. The mean and median decrease.

Mathematics
1 answer:
agasfer [191]2 years ago
8 0

Answer:

<h2>The mean decreases, and the median remains the same.</h2>

Step-by-step explanation:

Remember that a box plot is made by the quartiles of the distribution, the maximum value and the minimum value. So, from a box plot we can deduct the range, the median and the interquartile range.

In this case, the median remains the same at $9.5 per hour. The median is indicated by the middle line of the box, and you can observe that it doesn't change.

Now, the range of the data set decreases from 7 to 3.

On the other hand, the mean must decrease, because data greater than $11 doesn't exist in the box plot number 2, and the mean is a central measure sensible to those changes.

Therefore, the right answer is <em>The mean decreases, and the median remains the same.</em>

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jill mixes two types of concentrations od hci (hydrochloric acid) 0.375 liters of 25% hydrochloric acid and 0.625 liters of 65%
Sonja [21]

Answer:

The concentration of HCl in the mixture is 1L of 50% HCl

Step-by-step explanation:

Here, we want to know the percentage of HCl present which refers to the its concentration.

Firstly, the total volume we have is 0.375 + 0.625 = 1 L

we can calculate the percentage as follows;

The percentage of the 25% present is 37.5%

while the percentage of the 75% present is 62.5%

When we say the percentage present, we are referring to the amounts of the total liters which is 1 present.

So the concentration of the final mixture will be;

(37.5% of 25) + (62.5% of 65)

= 9.375% + 40.625%

Adding both gives = 50%

So the concentration we have is 1L of 50% HCl

7 0
2 years ago
A store manager is looking at past jewelry sales to determine what sizes of rings to keep in stock. The list shows the ring size
Rom4ik [11]
Mean: ( 9 + 7 + 6.5 + 7.5 + 7 + 8 + 5 + 6 + 7.5 + 8 ) : 10 = 7.15
Variance:
(Sigma)² = ( 1.85² + 0.15² + 0.65² + 0.35² + 0.15² + 0.85² + 2.15² + 1.15² + 0.35² + 0.85² ) : 10 ≈ 1.15
Answer: C ) 1.15
4 0
2 years ago
Read 2 more answers
Te probability is 0.5 that an artist makes a craf item with satisfactory quality. Assume the production of each craf item by thi
mina [271]

Answer:

The probability that at most 3 attempts are required to produce a craft item with satisfactory quality is 0.9375

Step-by-step explanation:

Let E be a random variable denoting the event that an artist makes a craft item with satisfactory level.

Then the random variable E follows a Geometric distribution.

A Geometric distribution is defined as the number of failures (<em>k</em>) before the first success.

The probability function of Geometric distribution is:

P(X=k)=(1-p)^{k}p, <em>p</em> = Probability of success and <em>k</em> = 0, 1, 2, 3...

The probability of success is, <em>p</em> = 0.5 and the number of failures is, <em>k</em> = 3.

Compute the probability of at most 3 attempts before the first success is:

P(X\leq 3) =P(X=3)+P(X = 2)+P(X=1) +P(X = 0)\\=[(1-0.5)^{0}*0.5]+[(1-0.5)^{1}*0.5]+[(1-0.5)^{2}*0.5]+[(1-0.5)^{3}*0.5]\\=0.9375

Therefore, the probability that at most 3 attempts are required to produce a craft item with satisfactory quality is 0.9375.

6 0
2 years ago
In a random sample of 90 students in first grade, the mean hours of sleep per night was 9.2 with a standard deviation of 0.37 in
ss7ja [257]

Answer:

Option C is right

Step-by-step explanation:

Given are two samples

I group has sample size 90, mean = 9.2 and std dev =0,.37

II group has sample size 70, mean = 7.3 and std dev = 0.58

we find that mean difference i.e. difference between mean hours of sleep between two groups

= 9.2-7.3 = 1.9

Std error for difference = 0.0620

Since sample size is sufficiently large we can use Z critical for 99%

i.e. 2.58

Margin of error =±2.58(0.062)

=0.16

Hence confidence interval 99% for difference in hours of sleep

= (1.9-0.16,1.9+0.16)

=(1.74, 2.06)


5 0
2 years ago
You have just spoken to your insurance agent and you are interested in investing in a 20-Payment Life insurance policy. Given th
Lesechka [4]

Answer: You can use this to help you out:

Determine the term life insurance amount per thousand on a 20-year-old male for a 10-year policy given that the face value of the policy is $65,000 and the annual premium is $291.85.

a.

$0.00449

c.

$0.2227

b.

$4.49

d.

$222.72

First find how many thousands on the amount of the face value

You do that by dividing the amount of the face value by 1000

65,000÷1,000=65

So the term life insurance amount per thousand is

291.85÷65=4.49...answer

Read more on Brainly.com - brainly.com/question/4241979#readmore

6 0
2 years ago
Read 2 more answers
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