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2 years ago

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A particular DSL modem operates at 768 kbits/sec. How many bytes can it receive in 1 minute? USB 3.0 can send data at 5 Gbits/se

c. How many bytes can it send in 1 minute?

1 answer:

igor_vitrenko [27]2 years ago

3 0

Answer:

a. 1.6 Kbytes/min

b. 10.417 Mbytes/min

Explanation:

a. The DSL modem operates at 768 Kbits/sec.

But,

8 bits = 1 byte and 1 Kbit = 1 000 bits, so that:

= $\frac{768 000}{8}$

= 96 000 bytes

Therefore, the modem operates at 96 Kbytes/sec.

The byte to be received in 1 minute can be calculated thus;

Since 60 seconds = 1 minute, then:

= $\frac{96000}{60}$

= 1600

= 1.6 Kbytes/min

The modem receives 1.6 Kbytes/min

b. The USB sends 5 Gbits/sec.

But, 8 bits = 1 byte and 1 Gbit = 1000000000 bits so that:

= $\frac{5000000000}{8}$

= 625000000

= 0.625 Gbytes

The USB sends 0.625 Gbyte/sec.

Since 60 seconds = 1 minute, then:

= $\frac{625000000}{60}$

= 10416666.67

= 10.417 Mbytes/min

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The ingredient weights for making 1 yd (cyd) of concrete by assuming aggregates in SSD state are given below. The volume of air

Pachacha [2.7K]

Answer:

Explanation:

Ans) Given batch weight of each component :

Cement = 700 lb

Water = 315 lb

Coarse aggregate = 1575 lb

Fine aggregate = 1100 lb

Part 1) Amount of water = 328.5 lb

Amount of water is needed to be increased if the aggregates has absorption capacity, To maintain constant water cement ratio, the mixing water is increased because some of the water is absorbed by aggregates.

Amount of water absorbed = 328.5 lb - 315 lb = 13.5 lb

Total amount of aggregates = 1575 + 1100 = 2675 lb

=> % Absorption capacity = 13.5 x 100 / 2675 = 0.5 %

Hence, new amount of Coarse aggregate = (1 - 0.005) x 1575 lb = 1567.125 lb

New amount of fine aggregate = (1 - 0.005) x 1100 = 1094.5 lb

Since, water cement ratio is maintained constant , amount of cement remains unchanged

=> Volume of water = 328.5 / 62.4 = 5.26 ft3

=> Volume of cement = 700 / (3.15 x 62.4) = 3.56 ft3

=> Volume of coarse aggregate = 1567.125 / (2.4 x 62.4) = 10.46 ft3

=> Volume of fine aggregate = 1100 / (2.4 x 62.4) = 7.34 ft3

Volume of air = 2% = 0.02 x 27 = 0.54 ft3

Total concrete volume = 5.26 + 3.56 + 10.46 + 7.34 + 0.54 \approx 27 ft3 = 1 yd3

Hence, calculated amount of each component is correct

Part 2) We know, minus sign indicated that the aggregate will absorb some moisture from concrete, hence mixing water amount needed to be corrected .

=> Amount of water absorbed by coarse aggregate = 0.01 x 1567.125 lb = 15.67 lb

=> Amount of water absorbed by fine aggregate = 0.02 x 1094.50 lb = 21.89 lb

Total amount of water absorbed = 15.67 + 21.89 = 37.56 lb

To maintain same water cement ratio, amount of mixing water is needed to be increased

=> Corrected amount of mixing water = 328.5 lb + 37.56 lb = 366 lb

=> Corrected amount of coarse aggregate = (1 - 0.01) x 1567.125 = 1551.45 lb

=> Corrected amount of fine aggregate = (1 - 0.02) x 1094.5 = 1072.6 lb

Part 3) We know,

Unit weight = Sum of weight of each material / Total volume

=> Sum of weight = 366 + 700 + 1551.45 + 1072.6 = 3690.05 lb

Total volume = 1 yd3 or 27 ft3

=> Expected Unit Weight = 3690.05 lb / 27 ft3 = 136.67 lb/ft3

Also, Concrete Yield = Weight of all components / Unit weight of concrete

=> Yield = 3690.05 / 136.67 = 27 ft3 or 1 yd3

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2 years ago

In a heat-treating process, a 1-kg metal part, initially at 1075 K, is quenched in a closed tank containing 100 kg of water, ini

storchak [24]

Answer:

attached below

Explanation:

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2 years ago

Natural Convection from an Oven Wall. The oven wall in Example 4.7-1 is insulated so that the surface temperature is 366.5 K ins

lukranit [14]

Answer:

i) Heat transfer coefficient (h) = 7 w/m²k

ii) Heat transfer per meter width of wall

= h x L x 1 x (Ts - T₆₀)

= 7 x 0.3048 x (505.4 - 322) = 414.747 w/m

Explanation:

see attached image

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2 years ago

During an experiment conducted in a room at 25°C, a laboratory assistant measures that a refrigerator that draws 2 kW of power h

zvonat [6]

Answer:

Not reasonable.

Explanation:

To solve this problem it is necessary to take into account the concepts related to the performance of a reversible refrigerator. The coefficient of performance is basically defined as the ratio between the heating or cooling provided and the electricity consumed. The higher coefficients are equivalent to lower operating costs. The coefficient can be greater than 1, because it is a percentage of the output: losses, other than the thermal efficiency ratio: input energy. For a reversible refrigerator the coefficient is given by

$COP_{R,rev} = \frac{1}{\frac{T_1}{T_2}-1}$

Where,

$T_1 =$ High temperature

$T_2 =$ Low Temperature

With our values previous given we can find it:

$T_2 = -30\°C = (-30+273)$

$T_2 = 243K$

$T_1 = 25\°C = (25+273)$

$T_1 = 298K$

With these values we can now calculate the coefficient of performance:

$COP_{R,rev} = \frac{1}{\frac{298}{243}-1}$

$COP_{R,rev} = 4.42$

At the same time we can calculate the work consumption of the refrigerator, this is

$W = \dot{W}\Delta t$

Where,

$\dot{W} =$ Required power input

t = time to remove heat from a cool to water medium

$W = 2kJ/s * 20 min$

$W = 2kJ/s * 1200s$

$W = 2400kJ$

In this way we can calculate the coefficient of the refrigerator directly:

$COP_R = \frac{Q_L}{W}$

Where,

Q = Amoun of heat rejected

$COP_R = \frac{30000}{2400}$

$COP_R = 12.5$

Comparing the values of both coefficients we have that the experiments are NOT reasonable, because the coefficient of a refrigerator is high compared to coefficient of reversible refrigerator.

5 0

2 years ago

Given the following code, what indexes must be passed to the substring method to produce the new String with the value "SCORE"?

Ierofanga [76]

Answer:

For expr1 = index 5, length 5

For expr2 = index 0, length 4 and index 21, length 5

string quote = "Four score and seven years ago";

string expr1 = quote.Substring(5, 5).ToUpper(); // "SCORE"

string expr2 = quote.Substring(0, 4) + quote.Substring(21, 5).ToLower(); // "fouryears"

Console.WriteLine(expr1);

Console.WriteLine(expr2);

Explanation:

Then code is written in c# and it produces SCORE and f

ouryears

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2 years ago