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kati45 [8]
2 years ago
11

Which of the following best completes the proof showing that ΔWXZ ~ ΔXYZ? triangles WXZ and XYZ that share side XZ with right an

gle XZW, WZ equals 12, XZ equals 6, and YZ equals 3 Since segment XZ is perpendicular to segment WY, angles WZX and XZY are both right angles and congruent. The proportion ________ shows the corresponding sides are proportional, so the triangles are similar by the SAS Similarity Postulate. 6 over 12 equals 3 over 6 6 over 3 equals 6 over 12 6 over 6 equals 3 over 12 12 over 6 equals 3 over 6
Mathematics
2 answers:
Ira Lisetskai [31]2 years ago
6 0

Answer:

16 over 12 equals 12 over 9

Step-by-step explanation:

SVEN [57.7K]2 years ago
4 0

Answer:

81

Step-by-step explanation:

6 over 12 equals 3 over 6 6 over 3 equals 6 over 12 6 over 6 equals 3 over 12 12 over 6 equals 3 over 6

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A group of 10 students participate in chess club, karate club, or neither.
Afina-wow [57]

Total number of students = 10

As we have to find

P(A/B) = Probability( A when B has happend)

P(A/B)= P(A intersection B)/P(B)

According to given figure only yolanda and Rob are in both club


Therefore,P(A intersection B) =\frac{2}{10}

Number of student in karate club =6

P(B)= \frac{6}{10}

P(A/B) = \frac{2}{10}\div{\frac{6}{10}


Converting division into multiplication by reciprocating the term after division



P(A/B) = \frac{2}{10}\times{\frac{10}{6}



On solving we get ,


P(A/B) = \frac{2}{6}

P(A/B)=\frac{1}{3}


P(A/B) =0.33

8 1
2 years ago
1 point) As reported in "Runner's World" magazine, the times of the finishers in the New York City 10 km run are normally distri
BigorU [14]

Answer:

(a) E (X) = 61 and SD (X) = 9

(b) E (Z) = 0 and SD (Z) = 1

Step-by-step explanation:

The time of the finishers in the New York City 10 km run are normally distributed with a mean,<em>μ</em> = 61 minutes and a standard deviation, <em>σ</em> = 9 minutes.

(a)

The random variable <em>X</em> is defined as the finishing time for the finishers.

Then the expected value of <em>X</em> is:

<em>E </em>(<em>X</em>) = 61 minutes

The variance of the random variable <em>X</em> is:

<em>V</em> (<em>X</em>) = (9 minutes)²

Then the standard deviation of the random variable <em>X</em> is:

<em>SD</em> (<em>X</em>) = 9 minutes

(b)

The random variable <em>Z</em> is the standardized form of the random variable <em>X</em>.

It is defined as:Z=\frac{X-\mu}{\sigma}

Compute the expected value of <em>Z</em> as follows:

E(Z)=E[\frac{X-\mu}{\sigma}]\\=\frac{E(X)-\mu}{\sigma}\\=\frac{61-61}{9}\\=0

The mean of <em>Z</em> is 0.

Compute the variance of <em>Z</em> as follows:

V(Z)=V[\frac{X-\mu}{\sigma}]\\=\frac{V(X)+V(\mu)}{\sigma^{2}}\\=\frac{V(X)}{\sigma^{2}}\\=\frac{9^{2}}{9^{2}}\\=1

The variance of <em>Z</em> is 1.

So the standard deviation is 1.

8 0
2 years ago
Which of the following is the graph of y = StartRoot negative x minus 3 EndRoot? On a coordinate plane, an absolute value curve
MariettaO [177]

Answer:

d

Step-by-step explanation:

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8 0
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There is only one granola bar left out of a pan of 10 bars. if Will and Rachel decide to split the last granola bar what fractio
lesantik [10]
1/20. I believe. One granola bar out of ten is 1/10 and half of a granola bar (or half of 1/10) is 1/20.
6 0
2 years ago
The range of scores in each interval of a grouped frequency distribution is called the
tamaranim1 [39]
The answer is class intervals. A big set of data are grouped into different classes to get a hint of the distribution, and the range of such class of data is known as the Class Interval. In other words, these are range of scores in a group frequency distribution. Class intervals are commonly equal in width and are mutually exclusive. The middle of an interval is called a class mark and the ends of a class interval are called class limits. To calculate the class interval, divide the range by the number of classes. 
3 0
2 years ago
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