<span>The possible values are less than 4 but greater than –4.</span>
Event: Probability: A. Too much enamel 0.18 B. Too little enamel 0.24 C. Uneven application 0.33 D. No defects noted 0.47
let P(AC) = x, P(BC) = y, then P(A) + P(B) + P(C) - (x+y) = 1-0.47 = 0.53 x+y = 0.22
3. The probability of paint defects that results to <span>an improper amount of paint and uneven application? </span>
P(A U B U C) = 0.53
4. <span>the probability of a paint defect that results to</span>
<span>the proper amount of paint, but uneven application?</span>
P(C) - P(AC) - P(BC) = 0.47 - 0.22 = 0.25
A and B are disjoint so P(ABC) = 0, but you can have P(AC) and P(BC). you can't compute these separately here, but you can compute P(AC) + P(BC). By the way, P(AC) eg is just an abbreviated version of P(A∩C).
So, on day 1, the plant was say "P" cm tall.
then 2 weeks go by, or 14 days, and the plant grew to 452 cm.
Answer:
Chessebuger
Step-by-step explanation:
see the chesse burger is real good
M + 20 = 9
u need to subtract 20 from both sides because u want to isolate m
m + 20 = 9
m + 20 - 20 = 9 - 20
m = - 11