The most probable number, in this case, would be by ratio,
32:48 = 360:x
cross multiply and solve for x
x=360*48/32=540
Ans. Most probably there are 540 students enrolled.
After 7 a.m., the power usage on a college campus increases at a rate of 21% per hour.
t be the number of hours
the power usage increases at a rate of 21% per hour
21% = 0.21, constant rate = 0.21 . So slope = 0.21
Prior to 7 a.m., 15,040 kWh have been used.
At 7.am , power used = 15,040kWh. so our y intercept is 15,040
We use slope intercept form y=mx+b
slope m = 0.21 and b = 15040
power usage , y = 0.21 t + 15040
The university has a daily goal to keep their power usage less than or equal to 100,000 kWh
Power usage is less than or equal to 100,000
So inequality becomes 0.21t + 15,040 <= 100,000
<span>10X3 tens in unit form is written:
10*3 tens = 30 tens = 300 units
10X3 tens in standard form:
10 x 3 tens = 10 x 30 = 300</span>
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin.
<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>
<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>
<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>
<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>
<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>
<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>
<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>
<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>
<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
Hey mark me brainlest but ur answer is 27/45
Bess ur day.
