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Stolb23 [73]
2 years ago
15

The ability of ecologists to identify regions of greatest species richness could have an impact on the preservation of genetic d

iversity, a major objective of the World Conservation Strategy. A study used a sample of n = 33 lakes to obtain the estimated regression equation
y = 3.89 + 0.033x1 + 0.024x2 + 0.023x3 − 0.0080x4 − 0.13x5 − 0.72x6
where y = species richness, x1 = watershed area, x2 = shore width, x3 = poor drainage (%), x4 = water color (total color units), x5 = sand (%), and x6 = alkalinity.
The SSR and SSE have been calculated to be:_________.
SSR = 752.25 and SSE = 300.9.
Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
5 0

ANSWER:

I believe you wish to calculate the sum of squares total (SST) for this regression analysis. The sum of squares total is 1053.15

Step-by-step explanation:

The sum of squares total is numerically derived by adding the sum of squares regression (regression sum of squares) to the sum of squares error (error sum of squares). The regression sum of squares here is 752.25 and the error sum of squares is 300.9

This gives us a total sum of squares of 1053.15

Sums of squares tell if a linear regression of one variable (or variables) on another is good or not.

The squared differences between the observed dependent variable and its mean is a measure of the total variability of the data set.

So the SST is equal to 752.25 + 300.9 = 1053.15

You might be interested in
Question 9 (3 points)
Mila [183]

From the dot plot, we have that 90.91% of the students have 5 or more vowels in their first and last  names.

---------------------

The dot plot states that:

  • 2 students have 4 vowels in their first and last name.
  • 3 students have 5 vowels.
  • 8 students have 6 vowels.
  • 9 students have 7 vowels.

Then:

  • Total of 2 + 3 + 8 + 9 = 22 students.
  • 3 + 8 + 9 = 20 have or more vowels.

p = \frac{20}{22} \times 100\% = 90.91\%

90.91% of the students have 5 or more vowels in their first and last  names.

A similar problem is given at brainly.com/question/14354536

5 0
2 years ago
Set R contains all integers from 10 to 125, inclusive, and Set T contains all integers from 82 to 174, inclusive. How many integ
SCORPION-xisa [38]

Answer: PLEASE GIVE BRAINLIEST

72 integers

Step-by-step explanation:

Starting From 82-174 every integer is included in T so every integer that is not included in T but included in R would be 82-10 so every integer from 10 to 82.

3 0
2 years ago
The figure below shows a line graph and two shaded triangles that are similar:Which statement about the slope of the line is tru
zzz [600]
Here is something to keep in mind. 
when there is a downward slope, the slope will ALWAYS have a negative slope. even if it is above the x-axis. negative slopes will tend to go from positive y-axis to negative y-axis 
so personally would have to go with -4
because the x-axis is by 4 each time. and this slope is going downward. 

your answer will be D

6 0
2 years ago
Read 2 more answers
Which function has the domain x>or= -11
iogann1982 [59]
I'm assuming this is multiple choice and you forgot to post the answers. I'll take a guess and say it probably looks something like this:
y = \sqrt{x + 11}
Because you can't take the square root of a negative number without getting an imaginary result, resulting in the function having a closed domain limit.
6 0
2 years ago
The number of bacteria in a petri dish on the first day was 113 cells. If the number of bacteria increase at a rate of 82% per d
Tresset [83]

Answer:

4107 cells

Step-by-step explanation:

From the question, we have the following values:

Day 1 : 113 cells

Number of cells increases by day by 82%

Hence,

Day 2

113 × 82% = 92.66cells

Hence, Total number of bacteria cells for Day 2 = 113 + 92.66 = 205.66cells

Day 3

205.66 × 82% = 168.6412 cells

Hence, Total number of bacteria cells for Day 3 = 168.6412 + 205.66 = 374.3012 cells

Day 4

374.3012 × 82% = 306.926984 cells

Hence, Total number of bacteria cells for Day 4 = 306.926984 + 374.3012 = 681.228184 cells

Day 5

681.228184 × 82% = 558.60711088 cells

Hence, Total number of bacteria cells for Day 5 = 558.60711088 + 681.228184 = 1239.8352949 cells

Day 6

1239.8352949 × 82% = 1016.6649418 cells

Hence, Total number of bacteria cells for Day 5 = 1016.6649418 + 1239.8352949 = 2256.5002367 cells

Day 7

2256.5002367 × 82% = 1850.3301941 cells

Hence, Total number of bacteria cells for Day 7 = 1850.3301941 + 2256.5002367 = 4106.8304308 cells

Approximately to nearest whole number, the total number of bacteria cells that would be present after 7 days = 4107 cells

3 0
2 years ago
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