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Kipish [7]
1 year ago
11

Planes Q and R are parallel. Lines a and b are shown on planes Q and R, respectively.

Mathematics
2 answers:
Vlad [161]1 year ago
8 0

Answer: I have included an image of the correct answer.

They are skew lines

AveGali [126]1 year ago
5 0

Answer:

Skew Lines

Step-by-step explanation

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Solve x2 + 6x = 7 by completing the square. Which is the solution set of the equation?
Ber [7]
So first you have to find the perfect square that matches up with x^2 + 6x

so half of 6, and square it. your perfect square is 9

x^2 + 6x + 9 = 7 + 9

then, condense the left side of the equation into a squared binomial:

(x + 3)^2 = 16

take the square root of both sides:

x + 3 = ± √16

therefore:

x + 3 = ± 4

x = - 3 ± 4

so your solution set is:

x = 1, -7
7 0
1 year ago
Read 2 more answers
Rita is planting saplings along her garden fence. When she started, she had x packages of saplings with 5 saplings per package.
Arturiano [62]

Answer:

<u>A. When Rita started, she had 7 packages of saplings.</u>

<u>B. If we represent x (number of packages of saplings) on a number line graph, it will start on number 4 (number of packages Rita still has) then moves to the right to number 7, that is the number of packages when Rita started to plant.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of packages Rita started = x

Number of saplings per package = 5

Number of saplings planted by Rita = 15

Number of saplings left = 20

2. How many packages of saplings did she start with?

Number of packages Rita started = (Number of saplings planted by Rita + Number of saplings left)/Number of saplings per package

Replacing with the real values:

x = (15 + 20)/5

x = 35/5 = 7

<u>When Rita started, she had 7 packages of saplings.</u>

3. What would the solution look like on a number line graph?

If we represent x (number of packages of saplings) on a number line graph, it will start on number 4 (number of packages Rita still has) then moves to the right to number 7, that is the number of packages when Rita started to plant.

5 0
2 years ago
Help me with this question please!
BigorU [14]

Answer:

c = 40d+20

Step-by-step explanation:

He has to pay 20 dollars and that can't multiply so the forty has to multiply and it would have to be by d because c is the total cost

6 0
1 year ago
Read 2 more answers
a square painting has an area of 81x^2-90x-25. A second square painting has an area of 25x^2+30x+9. What is an expression that r
galina1969 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ---->  the area of the second square painting

D -----> the difference of the areas

we have

A1=81x^{2}-90x-25

A2=25x^{2}+30x+9

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

D=(25x^{2}+30x+9)-(81x^{2}-90x-25)

D=(-56x^{2}+120x+34)

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

D=(81x^{2}-90x-25)-(25x^{2}+30x+9)

D=(56x^{2}-120x-34)

4 0
2 years ago
An online seed supplier packages a seed mix that costs the company $20.70 per pound. The mix includes poppy seeds costing $24.00
kati45 [8]

Answer:

The quantity of clover seeds the worker will add is 11.14 pounds

Step-by-step explanation:

Let

x=Poppy seed

y=clover seed

24x+13y=20.70(x+y)

x=26 pounds

Substitute x=26 pounds into the equation

24x+13y=20.70(x+y)

24(26)+13y=20.70(26+y)

624+13y=538.2 +20.70y

Collect like terms

624-538.2=20.70y-13y

85.8=7.7y

Divide both sides by 7.7

y=85.8/7.7

=11.14 pounds

Therefore, the quantity of clover seeds the worker will add is 11.14 pounds

8 0
2 years ago
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