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Kay [80]
2 years ago
5

To make 1 batch of vegetable soup, Sam needs 16 ounces of water and 8 ounces of vegetables. How does the amount of water compare

to the amount of vegetables?
Mathematics
1 answer:
BARSIC [14]2 years ago
4 0
The amount of water is double in comparison to the amount of vegetables.
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Which congruence theorem can be used to prove △BDA ≅ △DBC? Triangles B D A and D B C share side D B. Angles C B D and A D B are
Tomtit [17]

Answer:

A. Hypotenuse-leg (HL) congruence.

HL, when you have 2 right triangles and their hypotenuses are congruent you are able to say HL

Step-by-step explanation:

We know that the hypotenuse-leg theorem states that if the hypotenuse and one leg of a right triangle are congruent to hypotenuse and corresponding leg of another right triangle, then the triangles are congruent.  

hypotenuse(AB) of △BDA equals to hypotenuse (CD) of △DBC.  

BDA and DBC share a common side DB.

Using Pythagorean theorem we will get,

CD^{2}=DB^{2}+BC^{2}...(1)  \\\\AB^{2}=DB^{2}+AD^{2}...(2)

We have been given that CD=AB, Upon using this information we will get,

DB^{2}+BC^{2}=DB^{2}+AD^{2}

Upon subtracting DB^{2} from both sides of our equation we will get,

BC^{2}=AD^{2}\\\\BC=AD

<h3>Therefore, by HL congruence △BDA ≅ △DBC.</h3>
6 0
2 years ago
Read 2 more answers
A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
2 years ago
Mackenzie has a loyalty card good for a 20% discount at her local hardware store. What would her total in dollars and cents be,
8_murik_8 [283]

Answer: $14.0

Step-by-step explanation:

For us to calculate this question, we have to find 20% of $17.45 and then subtract the value gotten from $17.45. This will be:

= $17.45 - (20% × $17.45)

= $17.45 - (0.2 × $17.45)

= $17.45 - $3.49

= $13.96

= $14.0 to nearest cent

6 0
2 years ago
Read 2 more answers
Math 9:The floor of conference hall can be covered completely with tiles. Its length is 36 ft longer than its width. The area of
valentina_108 [34]
What is the question?
I'm assuming it is to find the length and width.
+_= plus or minus
(X+36)
____________
| |
(X) | |
|____________|

X^2+36X-2040<0
X<-36+_(36^2-4*-2040)^(1/2)
-----------------------------------
2
X<-18+_2((591)^(1/2))
This is probably not what you wanted, sorry
8 0
2 years ago
Compare the mathematical meaning of the word limit with its commonly used meanings. For the word’s mathematical meaning, think o
vredina [299]
This is<span> not the exact, precise </span>definition<span> of a </span>limit. If you would like to see the more precise and mathematical definition<span> of a </span>limit<span> you should check out the The </span>Definition<span> of a </span>Limit<span> section at the end of this chapter. The </span>definition<span> given above </span>is<span> more of a “working” </span>definition<span>.</span>
4 0
2 years ago
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