Answer:
19.71 ms
Explanation:
The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.
Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms
Head movement time from track 8 to track 9 = seek time = 2 ms
rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms
The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms
Answer:
Since the attack impacts the client SANS Critical Security Controls. This act affects the Inventory of authorized and unauthorized software running on the victim's machine.
Answer:
your friend just sent you 32 bits of pixel data (just the 0s and 1s for black and white pixels) that were encoded after sampling an image. Choose the two statements that are true.
------------------
The 32 bits of pixel data is enough to produce the image using the widget. Nothing else is needed.
------------------------
The digital image would be an exact copy of the analog image.
-----------------------------The correct width and height must be input into the pixelation widget to produce the image.
---------------------------The fact that only 32 bits were used to represent the image indicates relatively large sample squares were used. The digital image may vary from the analog image significantly
Explanation:
Here you go,
Import java.util.scanner
public class SumOfMax {
public static double findMax(double num1, double num2) {
double maxVal = 0.0;
// Note: if-else statements need not be understood to
// complete this activity
if (num1 > num2) { // if num1 is greater than num2,
maxVal = num1; // then num1 is the maxVal.
}
else { // Otherwise,
maxVal = num2; // num2 is the maxVal.
}
return maxVal;
}
public static void main(String[] args) {
double numA = 5.0;
double numB = 10.0;
double numY = 3.0;
double numZ = 7.0;
double maxSum = 0.0;
/* Your solution goes here */
maxSum = findMax(numA, numB); // first call of findMax
maxSum = maxSum + findMax(numY, numZ); // second call
System.out.print("maxSum is: " + maxSum);
return;
}
}
/*
Output:
maxSum is: 17.0
*/
