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RSB [31]
2 years ago
12

The ball of dough hits the floor and does not rebound.

Physics
1 answer:
tekilochka [14]2 years ago
8 0

Answer:

When the ball goes down its mechanical energy is conserved, ust before touching the ground all the energy is kinetic

When the ball touches the floor, energy has been converted into potential and heat, by the deformation of the ball.

Explanation:

When the ball goes down its mechanical energy is conserved, this is the power energy due to the height it is converted into kinetic energy to medicad that falls, just before touching the ground all the energy is kinetic.

When the ball touches the floor, the kinetic energy is not conserved, but if we define a system formed by the ball and the floor, the amount of movement is conserved, this being an inelastic shock, because the bla and the floor are stuck, so which energy has been converted into potential and  energized and heat by the deformation of the ball.

   Consequently all the mechanical energy that the ball brings before reaching the ground was converted into potential energy and heat during the crash.

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8m/s

Explanation:

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The current supplied by a battery slowly decreases as the battery runs down. Suppose that the current as a function of time is:
ludmilkaskok [199]

Answer: 8.1 x 10^24

Explanation:

I(t) = (0.6 A) e^(-t/6 hr)

I'll leave out units for neatness: I(t) = 0.6e^(-t/6)

If t is in seconds then since 1hr = 3600s: I(t) = 0.6e^(-t/(6 x 3600) ).

For neatness let k = 1/(6x3600) = 4.63x10^-5, then:

I(t) = 0.6e^(-kt)

Providing t is in seconds, total charge Q in coulombs is

Q= ∫ I(t).dt evaluated from t=0 to t=∞.

Q = ∫(0.6e^(-kt)

= (0.6/-k)e^(-kt) evaluated from t=0 to t=∞.

= -(0.6/k)[e^-∞ - e^-0]

= -0.6/k[0 - 1]

= 0.6/k

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5 0
2 years ago
A physics department has a Foucault pendulum, a long-period pendulum suspended from the ceiling. The pendulum has an electric ci
antoniya [11.8K]

Answer:

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Using this equation

.5A=Ae^(-t/T)

The .5A is half the amplitude

Take ln of both sides to get ride of Ae

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Now rearrange to = T

T=-2220/ln(.5) = 3202.78sec / 60 secs = 53.38 mins -> first part of the answer.

The second part is really easy. It took 37 mins to decay half way. meaning to decay another half of 50% which equals 25% it will take an additional 37 mins!

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Fnet=7200 N

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