All categories

2 years ago

It takes 3 minutes to make toast in a 1500 watt toaster. Calculate how much work is done by the toaster.

2 answers:

6 0

Hello there.

It takes 3 minutes to make toast in a 1500 watt toaster. Calculate how much work is done by the toaster.

270,000 J

Aleks [24]2 years ago

3 0

Answer: The work done by the toaster is 270,000 J

Explanation:

Power is defined as the ratio of rate of work done by an object with respect to time.

Mathematically,

$P=\frac{W}{t}$

where,

P = power of the toaster = 1500 W

W = work done by the toaster = ?

t = time taken = 3 mins = 180 sec (Conversion factor: 1 min = 60 sec)

Putting values in above equation, we get:

$1500W=\frac{W}{180s}\\\\W=(1500W\times 180s)=270,000J$

Hence, the work done by the toaster is 270,000 J

You might be interested in

An object is moving in the plane according to these parametric equations:

aniked [119]

A. The horizontal velocity is
vx = dx/dt = π - 4πsin (4πt + π/2)
vx = π - 4π sin (0 + π/2)
vx = π - 4π (1)
vx = -3π

b. vy = 4π cos (4πt + π/2)
vy = 0

c. m = sin(4πt + π/2) / [πt + cos(4πt + π/2)]

d. m = sin(4π/6 + π/2) / [π/6 + cos(4π/6 + π/2)]

e. t = -1.0

f. t = -0.35

g. Solve for t
vx = π - 4πsin (4πt + π/2) = 0
Then substitute back to solve for vxmax

h. Solve for t
vy = 4π cos (4πt + π/2) = 0
The substitute back to solve for vymax

i. s(t) = [x(t)^2 + y(t)^2]^(1/2)

h. s'(t) = d [x(t)^2 + y(t)^2]^(1/2) / dt

k and l. Solve for the values of t
d [x(t)^2 + y(t)^2]^(1/2) / dt = 0
And substitute to determine the maximum and minimum speeds.

5 0

2 years ago

Read 2 more answers

A baseball pitcher throws a ball at 90.0 mi/h in the horizontal direction. How far does the ball fall vertically by the time it

Lisa [10]

Answer:

Vertical distance= 3.3803ft

Explanation:

First with the speed of the ball and the distance traveled horizontally we can determine the flight time to reach the plate:

Velocity= (90 mi/h) × (1 mile/5280ft) = 475200ft/h

Distance= Velocity × time⇒ time= 60.5ft / (475200ft/h) = 0.00012731h

time= 0.00012731h × (3600s/h)= 0.458316s

With this time we can determine the distance traveled vertically taking into account that its initial vertical velocity is zero and its acceleration is that of gravity, 9.81m/s²:

Vertical distance= (1/2) × 9.81 (m/s²) × (0.458316s)²=1.0303m

Vertical distance= 1.0303m × (1ft/0.3048m) = 3.3803ft

This is the vertical distance traveled by the ball from the time it is thrown by the pitcher until it reaches the plate, regardless of air resistance.

3 0

2 years ago

A machine part is vibrating along the x-axis in simple harmonic motion with a period of 0.27 s and a range (from the maximum in

Gnoma [55]

Answer:

$x = -1.437 cm$

Explanation:

The general equation for position of Simple harmonic motion is given as:

$x = A sin(\omega t)$ ........(1)

where,

x = Position of the wave

A = Amplitude of the wave

ω = Angular velocity

t = time

In this case, the amplitude is just half the range,

thus,

$A =\frac{3cm}{2}=1.5cm$ (Given range = 3cm)

A = 1.5 cm

Now, The angular velocity is given as:

$\omega=\frac{2\pi}{T}$

Where, T = time period of the wave =0.27s (given)

$\omega=\frac{2\pi}{0.27s}$

$\omega=23.27s^{-1}$

so, at time t = 55 s, the equation (1) becomes as:

$x = 1.5 sin(23.27\times 55)$

on solving the above equation we get,

$x = -1.437 cm$

here the negative sign depicts the position in the opposite direction of +x

5 0

2 years ago

If the voltage amplitude across an 8.50-nF capacitor is equal to 12.0 V when the current amplitude through it is 3.33 mA, the fr

Dmitriy789 [7]

Answer:

Frequency will be equal to 5.20 kHz

So option (c) will be correct answer

Explanation:

We have given value of capacitance $C=8.5nF=8.5\times 10^{-9}f$

Potential difference across capacitor V = 12 volt

Current through capacitor $i=3.33mA=3.33\times 10^{-3}A$

Capacitive reactance will be equal to $X_c=\frac{V}{i}=\frac{12}{3.33\times 10^{-3}A}=3603.60ohm$

Capacitive reactance is equal to $X_c=\frac{1}{\omega C}$

$3603.60=\frac{1}{\omega\times 8.5\times 10^{-9}}$

$\omega =32647.091rad/sec$

$2\pi f=32647.091$

$f=5198.98Hz$

f = 5.20 kHz

So frequency will be equal to 5.20 kHz

So option (c) will be correct answer

3 0

2 years ago

The amount of pressure required to move a 6800 lb force with a 6" d piston is ___ psi.

Katena32 [7]

The pressure needed in PSI = Pounds of force needed divided by the cylinder Area
The Cylinder rod Area is 21.19 sq inches
Thus, the pressure= 6800/21.19
= 320.91 PSI

7 0

2 years ago