A student throws a 0.22 kg rock horizontally at 20.0 m/s from 10.0 m above the ground. Find the initial kinetic energy of the ro
1 answer:
Answer:
44J
Explanation:
Given parameters:
Mass of rock = 0.22kg
Initial velocity = 20m/s
Distance moved = 10m
Unknown:
Initial kinetic energy of the rock = ?
Solution:
To solve this problem, we need to understand that kinetic energy is the energy due to the motion of a body.
It is mathematically expressed as;
Kinetic energy = m v²
m is the mass
v is the velocity
Kinetic energy = x 0.22 x 20² = 44J
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Answer:
Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis
Explanation:
The stiff wire 50.0cm long bent at a right angle in the middle
One section lies along the z axis and the other is along the line y=2x in the xy plane
tan θ = 2
Therefore,
slope m = tan θ = y / x
Then length of each section is 25.0cm
so, length vector of the wire is
And magnetic field is B = (0.318T)i
Therefore,
Magnitude of the force is
Direction is
Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis