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goldenfox [79]
2 years ago
7

Urban cities like Atlanta have to contend with a serious problem like pollution. Drivers in California are testing out a car tha

t is fueled by hyrodgen; therefore, the emissions produced are water vapor. Read the article from the link below and answer the following questions:
goo.gl/h93L43

1. What does the author mean by the statement:
“If we’re really going to make a significant reduction in carbon emissions, you can only do that with fuel-cell vehicles in the mix"?

2. What are some of the challenges with these type of vehicles? How can these challenges be overcome?

3. Do you think fuel celled cars are a viable answer to decrease pollution why or why not?
Physics
1 answer:
riadik2000 [5.3K]2 years ago
4 0

1. With this statement, the author is referring to the fact that the vehicles are one of the largest polluters of the air. In order to reduce the pollution, the vehicles that are used will need to be changed, and with it the pollution will decrease significantly. The reduction of the pollution will come because the vehicles on hydrogen will not cause any pollution, so the enormous amounts of carbon dioxide released from the combustion of the engines will be thing of the past.

2. There are several challenges with this type of vehicles in order for them to replace the fossil fuel driven ones. The big price is one of the factors, as the majority of the people can not afford these cars. Another problem is that these vehicles are not as fast as the fossil fuel driven ones, and lot of people enjoy fast driving, despite it not being safe. There are millions of vehicles out there on the roads, and changing all of them with hydrogen vehicles will take a lot of time, as lot of those vehicles are new ones, so the people will not be willing to just throw them away and leave them rot in their garages. In order for the change of the driving park to be accomplished, the prices should go down, the people to be more serious about the environment and its protection, and patience as several decades will probably be needed for a change like this to be competed.

3. The fuel celled cars are a viable answer to decrease the pollution, as they are not causing any pollution, but instead will stop the process of large emissions of carbon dioxide from the fossil fueled cars. While this method is a good one, it should not be the only, as on its own it can not have the desirable effect, but instead all the major polluters should be included in the process. The industry and the production of energy are one of the major polluters as well, so they will need to follow the example, as if they not, the problem will stay, considering that the industry is constantly growing and the demand for energy is constantly growing too.

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Using kinematics, approximately 10.1 seconds
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Two bricks are resting on the edge of the lab table. Shirley Sheshort stands on her toes and spots the two bricks. She acquires
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Explanation:

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Air at 105 kPa and 37°C flows upward through a 6-cm-diameter inclined duct at a rate of 65 L/s. The duct diameter is then reduce
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Answer:

h=2.5456\ m

Explanation:

Given:

  • pressure of air in the duct, P_1=105\ kPa
  • temperature of air in the duct, T_1=37^{\circ}C
  • diameter of the duct, d_d=0.06\ m
  • flow rate through the duct, \dot V_1=65\ L.s^{-1}=0.065\ m^3.s^{-1}
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  • difference in the datum of the two points, z_2=0.2\ m

<u>Using continuity equation:</u>

\dot V_1=\dot V_2

\therefore \dot V_2=0.065\ m^3.s^{-1}

As we know,

\dot V_2=A_2.v_2

A_2=\pi\times \frac{d_r^2}{4}

A_2=\pi\times \frac{0.04^2}{4}

A_2=\pi\times 10^{-4}\ m^3.s^{-1}

Hence:

v_2=\frac{\dot V}{A_2}

v_2=\frac{0.065}{\pi\times 10^{-4}}

v_2=206.9\ m.s^{-1}

And:

v_1=\frac{\dot V_1}{A_1}

v_1=0.065\div \pi \times \frac{0.06^2}{4}

v_1=22.99\ m.s^{-1}

<u>According to Bernoulli's principle we have for an incomprehensible flow:</u>

\frac{P}{\rho.g} +\frac{v^2}{2g} +z=constt.

<u>Now we're concerned about the density of air:</u>

P.V=m.R.T

\rho=\frac{P}{R.T}

\rho=\frac{105000}{0.167\times 310}

\rho=1.18\ kg.m^{-3}

Apply Bernoulli's principle assuming it an in-compressible flow:

\frac{P_1}{\rho.g} +\frac{v_1^2}{2g} +z_1=\frac{P_2}{\rho.g} +\frac{v_2^2}{2g} +z_2

\frac{105000}{1.18\times 9.8} +\frac{22.99^2}{2\times 9.8} +0=\frac{P_2}{1.18\times 9.8} +\frac{206.9^2}{2\times 9.8} +0.2

P_2=80053.04\ Pa

<u>Now the difference in pressure:</u>

\Delta P=105000-80053.04

\Delta P=24946.96\ Pa

∴The corresponding difference in the water levels of manometer:

\Delta P=\rho.g.h

24946.96=1000\times9.8\times h

h=2.5456\ m

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Answer:

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Explanation:

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A stone is thrown into a pond. Five waves were made from the same source in 10 seconds.
lina2011 [118]

Answer:

The Frequency of the wave is 0.2Hertz

The period is 2seconds

Explanation:

We are asked to find the frequency and period

Frequency is the number of oscillations completed in one seconds

If five waves were made from the same source in 10 seconds, hence;

Frequency = number of oscillation/Time

Frequency = 5/10

Frequency = 0.5Hertz

Next is to get the period

Period = 1/Frequency

Period = 1/0.5

Period = 2seconds

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