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Vaselesa [24]
1 year ago
15

Two spherical objects have masses of 200 kg and 500 kg. Their centers are separated by a distance of 25 m. Find the gravitationa

l attraction between them.
Physics
1 answer:
ElenaW [278]1 year ago
8 0

Answer:

1.07 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1 = 200kg

Mass 2  = 500kg

Distance of separation  = 25m

Unknown:

Gravitational attraction between the two bodies  = ?

Solution:

To solve this problem, we use the equation of the universal gravitation;

                 F  = \frac{G mass 1  x mass 2}{r^{2} }  

G is the universal gravitation constant  = 6.67 x 10⁻¹¹Nm²kg⁻²

r is the distance

 Now insert the parameters and solve;

    F  = \frac{6.67 x 10^{-11} x 200 x 500 }{25^{2} }   = 1.07 x 10⁻⁸N

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Answer:

F=UR

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Answer:

The value is t_1 =  9 \  s

Explanation:

Generally the velocity attained by the sled after t = 3.10 s is mathematically evaluated using the kinematic equation as follows

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a = 13.5 m/s^2

So

v  =  0   +  13.5 *  3.10

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s =  u *  t  +  \frac{1}{2} a *  t^2

=> s =  +  \frac{1}{2} * 13.5 *  3.10^2

=> s =64.87

Now when sled stops its the final velocity is v_f =  0 m/s while the initial velocity will be the velocity after its acceleration i.e v  =  41.85 \ m/s

So

v_f  =  v  +  a_1t_1

Here  a_1 =  - 4.65, the negative sign shows that it is deceleration

So

           0  =  41.85  - 4.65 *  t_1

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If it were possible to remove gravity and friction, think about what would happen to a football if it were tossed into the air.
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Ignoring fluid resistance, football will <span>maintain a constant speed until other forces accelerate the football.</span>
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The equilibrium fraction of lattice sites that are vacant in silver (Ag) at 600°C is 1 × 10-6. Calculate the number of vacancies
algol [13]

Answer :

The number of vacancies (per meter cube) = 5.778 × 10^22/m^3.

Explanation:

Given,

Atomic mass of silver = 107.87 g/mol

Density of silver = 10.35 g/cm^3

Converting to g/m^3,

= 10.35 g/cm^3 × 10^6cm^3/m^3

= 10.35 × 10^6 g/m^3

Avogadro's number = 6.022 × 10^23 atoms/mol

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Where,

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Da = Density of silver

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The number of vacancies (per meter cube) = 5.778 × 10^28 × 1 × 10^-6

= 5.778 × 10^22/m^3.

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